Answer:
x=-1, y = 2, z = 1
Step-by-step explanation:
We are given with three equations and we are asked to find the solution to them.
2x + 2y + 3z = 5 ------------- (A)
6x + 3y + 6z = 6 --------------(B)
3x + 4y + 4z = 9 ---------------(C)
Step 1 .
multiplying equation (A) by 3 and subtracting B from the result
6x + 6y + 9z = 15
6x + 3y + 6z = 6
- - - = -
_______________
3y+3z=9
y+z=3
y=3-z ----------------- (C)
Step 2.
Substituting this value of y in equation B and C
6x + 3(3-z) + 6z = 6
6x+9-3z+6z=6
6x+3z=-3
2x+z=-1 ----------------(D)
3x + 4(3-z) + 4z = 9
3x+12-4z+4z=9
3x=-3
x=-1 ------------ (E)
Putting this value f x in (D)
2(-1)+z=-1
-2+z=-1
z=1
Now we put this value of z in equation (C)
y=3-z
y=3-1
y=2
Hence we have
x=-1, y=2 and z=1
<span>y = sqrt(25-x^2) at point (3,4)
The derivative gives us the slope at 3 to be:
-2x
------------ at x=3: -3/4
2sqrt(25-x^2)
</span><span>so we have a vector that is parallel to the slope of the tangent line is: <4,-3>
</span>
<span>the mag = 5 so; unit tangent = <4/5 , -3/5>
</span>
<span>since perpendicular lines have a -1 product between slopes we get the normal to be...
<3/5,4/5>
</span>
<span>It is <4,-3> because it is rise over run. Rise is y component of vector and run is x component of vector.</span>
Answer:
the answer is A on Edge
A) The limit does not exist because the values of h(x) seem to oscillate between random values around x = 9.
Step-by-step explanation:
took the quiz :)
It is a right triangle because a 3, 4, 5 triangle is always a right triangle. it is because it is a Pythagorean Triple. all the sides are whole numbers
