<span>30 hours
For this problem, going to assume that the actual flow rate for both pipes is constant for the entire duration of either filling or emptying the pool. The pipe to fill the pool I'll consider to have a value of 1/12 while the drain that empties the pool will have a value of 1/20. With those values, the equation that expresses how many hour it will take to fill the pool while the drain is open becomes:
X(1/12 - 1/20) = 1
Now solve for X
X(5/60 - 3/60) = 1
X(2/60) = 1
X(1/30) = 1
X/30 = 1
X = 30
To check the answer, let's see how much water would have been added over 30 hours.
30/12 = 2.5
So 2 and a half pools worth of water would have been added. Now how much would be removed?
30/20 = 1.5
And 1 and half pools worth would have been removed. So the amount left in the pool is
2.5 - 1.5 = 1
And that's exactly the amount needed.</span>
Answer:
x^3-1
Step-by-step explanation:
f(x)=g(x)-1 since was shifted down 1 unit x^3-1
f(x)=g(x)+1 would have been a shift up of 1 unit x^3+1
f(x)=g(x-1) shifted right 1 unit (x-1)^3
f(x)=g(x+1) shifted left one unit (x+1)^3
Anyways the answer is f(x)=x^3-1
Answer:
The current population (in 2005) is 4000 because it is the constant. The slope tells us how many people are added to the population, so 70 per year. For ex. 2008 (2008- 2005 = 3=> 3 x 70 = 210 => 210 + 4000 = 4210).
Abs are not getting mad annoying you
I need to learn about my solcoil studdyes
