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LiRa [457]
3 years ago
12

I need help and explanations with these 5 questions.Question 1Is the expression x^3*x^3*x^3equivalent to x^(3*3*3)? Why or why n

ot? Explain your reasoning.No because the law of exponentsQuestion 2Rewrite in simplest radical form1/x^((-3)/6)Show each step of your process.Question 3Rewrite in simplest rational exponent form √x • 4√x. Show each step of your process.Question 4Rewrite in simplest radical formx^(5/6)/x^(1/6)Show each step of your process.Question 5Which of the following expressions are equivalent? Justify your reasoning.a. 4√x3b. 1/x^(-1)c. 10√x5•x4•x2d. x^(1/3)*x^(1/3)*x^(1/3)

Mathematics
1 answer:
Bess [88]3 years ago
6 0

Answer:

1) No. 2) \sqrt{x} 3)4x 4) x^{\frac{3}{2}} or \sqrt{x^3}5) B and D.

Step-by-step explanation:

Check the pictures below

1) x^{3} *x^{3}*x^{3}=x^{3+3+3}=x^{9}x^(3*3*3)=x^{27}[/tex]

For the first, we must just  repeat the base e sum the exponents

For the second one, we must multiply the exponents.

According to the Exponents Law.

x^{m}*x^{n} =x^{m+n}\\x^{m*n} =x^{mn}

2)

Here we have three combined Exponent laws, namely:

3)

First on multiplying keep the 4 outside the square root,

4) The starting point of it is reminding that in a fraction, whenever we divide two fractions we have to operate the product of the first fraction times the inverse of the second one.

Then we apply the Exponent Law of a divison between same base powers, repeating the base subtracting the exponents, and simplifying it:

x^{\frac{4}{6}}=x^{\frac{3}{2}}

5)

Check below

b and d, are equivalent between themselves since the same quantities of x are displayed. Notice, all we have used. Exponent Laws and Power Properties

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Natalie needs to save $479.58 for a vacation. She saved $149.88, and earns $7.85 an hour working at the grocery store. How many
SashulF [63]

Answer:

42 hours

Step-by-step explanation:

Natalie needs to save a total of $479.58

She already saved $149.98

The amount left to save is

= 479.58-149.98

= 329.7

If she earns 7.85 dollars working per hour then the number of hours she can work to get $329.7 can be calculated as follows

= 329.7 / 7.85

= 42

Hence Natalie will work for 42 hours to meet her goals

6 0
3 years ago
Solve the system using elimination. Write the solution as an ordered pair. (1 point) SHOW YOUR WORK FOR FULL CREDIT! (2 points)
Gre4nikov [31]

Answer: (1,-1)

Step-by-step explanation:

- You can multiply the first equation by -1

- Add the equations.

- Solve for x, as following:

\left \{ {{-5x - 4y = -1} \atop {-3x + 4y = -7}} \right.\\------\\-8x=-8\\x=1

- Substitute the value of x into any of the original equations and then you must solve for y:

5(1)+4(y)=1\\4y=-4\\y=-1

Therefore, the solution is: (1,-1)

5 0
3 years ago
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Is it rational or irrational?
ElenaW [278]
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Work out the equation of the line which has a gradient of -2 and passes through the point (1,7)
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Answer:

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3 years ago
Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2
fredd [130]

Answer:

Both get the same results that is,

\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

Step-by-step explanation:

Given :

\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

and initial population,

\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]

a) - After two times, we will find in each position.

P_2=[P].[M]^2=[P].[M].[M]

M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

     =\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]

b) - With in migration process, 500 people are numbered. There will be after a long time,

After\;inifinite\;period=[M]^n.[P]

Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

                                   =\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

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3 years ago
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