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LiRa [457]
3 years ago
12

I need help and explanations with these 5 questions.Question 1Is the expression x^3*x^3*x^3equivalent to x^(3*3*3)? Why or why n

ot? Explain your reasoning.No because the law of exponentsQuestion 2Rewrite in simplest radical form1/x^((-3)/6)Show each step of your process.Question 3Rewrite in simplest rational exponent form √x • 4√x. Show each step of your process.Question 4Rewrite in simplest radical formx^(5/6)/x^(1/6)Show each step of your process.Question 5Which of the following expressions are equivalent? Justify your reasoning.a. 4√x3b. 1/x^(-1)c. 10√x5•x4•x2d. x^(1/3)*x^(1/3)*x^(1/3)

Mathematics
1 answer:
Bess [88]3 years ago
6 0

Answer:

1) No. 2) \sqrt{x} 3)4x 4) x^{\frac{3}{2}} or \sqrt{x^3}5) B and D.

Step-by-step explanation:

Check the pictures below

1) x^{3} *x^{3}*x^{3}=x^{3+3+3}=x^{9}x^(3*3*3)=x^{27}[/tex]

For the first, we must just  repeat the base e sum the exponents

For the second one, we must multiply the exponents.

According to the Exponents Law.

x^{m}*x^{n} =x^{m+n}\\x^{m*n} =x^{mn}

2)

Here we have three combined Exponent laws, namely:

3)

First on multiplying keep the 4 outside the square root,

4) The starting point of it is reminding that in a fraction, whenever we divide two fractions we have to operate the product of the first fraction times the inverse of the second one.

Then we apply the Exponent Law of a divison between same base powers, repeating the base subtracting the exponents, and simplifying it:

x^{\frac{4}{6}}=x^{\frac{3}{2}}

5)

Check below

b and d, are equivalent between themselves since the same quantities of x are displayed. Notice, all we have used. Exponent Laws and Power Properties

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4= -2(x-2) +4 please help I’ll give you points!
Elina [12.6K]
<h3>Solution:</h3>

4 = -2(x-2) + 4

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At 3pm, the length of the shadow of a thin vertical pole standing on level ground is the same as the height of the pole. A while
aliya0001 [1]

Answer: The height of the pole is 175.97 ( approx )

Step-by-step explanation:

Let the height of the pole is x cm,

Also, let the angle of elevation of the sun to the pole at 3 pm is \theta

Thus, by the question,

tan\theta = \frac{\text{ The height of the pole}}{\text{ The height of the shadow}}

\implies tan\theta = \frac{x}{x}    ( at 3pm the height of shadow = height of the pole)

\implies tan\theta = 1

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Again, according to the question,

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4 0
3 years ago
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