This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
F(x) can be written as:
f(x) = Asin(2x); where A is the amplitude and the period of the function is half that of a normal sin function.
f(π/4) = 4
4 = Asin(2(π/4))
4 = Asin(π/2)
A = 4
Amplitude of g(x) = 1/2 * amplitude of f(x)
A for g(x) = 2
g(x) = 2sin(x)
Answer:
I don't know what, I would like to know
Answer:
45 children
Step-by-step explanation:
30% of 150=45
Answer:
Step-by-step explanation:
Perimeter of rectangle = 208 m
2*(l + w) = 208 {divide both sides by 2}
l +w = 208/2
l +w = 104
l = 104 - w
Area of rectangle = 2415 square meters
l*w = 2415
Substitute l = 104 - w in the above equation,
(104 - w ) *w = 2415
104w - w² = 2415
0 = 2415 - 104w + w²
w² - 104w + 2415 = 0
Sum = -104
Product = 2415
Factors = (-69) , (-35)
w² - 35w - 69w + (-69)*(-35) = 0
w(w - 35) - 69(w - 35) = 0
(w -35)(w -69)
w - 35 = 0 ; w -69 = 0
w = 35 ; w = 69
The dimensions of the building: 35 , 69
