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vredina [299]
3 years ago
11

It takes the staff 7.2 hours to clean 27 rooms in hotel many hours would it take them to clean 15 room? srep by step​

Mathematics
1 answer:
Alinara [238K]3 years ago
5 0

Answer:

4

Step-by-step explanation:

The staffs takes 7.2 hours to clean 27 rooms

Therefore in one hour, the number of rooms cleaned is

= 7.2/27

= 0.2666

The number of hours required to 15 rooms is

= 0.2666×15

= 4 hours

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A triangle has side lengths 4 inches 5 inches and 7 inches. is the triangle a right triangle
garri49 [273]
Hey there!

Yes this triangle is a right triangle. Leg lengths 4 and 5 in. would be the legs and the 7 inch would be the hypotenuse.

Hope this helped!
3 0
3 years ago
Calculate the equation of a line passing through C(4;7) and D(9;17)
Ludmilka [50]

Answer:

it would be 10/5 or 2

Step-by-step explanation:

y2-y1/x2-x1

17-7/9-4

10/5 simplify

2

3 0
3 years ago
The volume of a spherical sculpture is 256 ft³. Rhianna wants to estimate the surface area of the sculpture. To do the estimate,
Brrunno [24]

Answer:

192 ft^2

Step-by-step explanation:

Given that

Volume of spherical sculpture = 256 ft³

\pi is used as 3.

To find:

Surface area of sculpture = ?

Solution:

First of all, let us learn about the formula for Volume and Surface Area of Sphere:

1. Volume =\frac{4}{3}\pi r^3

2. Surface\ Area = 4\pi r^2

Given volume is 256 ft³.

256 = \dfrac{4}{3}\pi r^3\\\Rightarrow 256 = \dfrac{4}{3}\times 3 r^3\\\Rightarrow 256 = 4 r^3\\\Rightarrow r^3=64\\\Rightarrow \bold{r = 4\ ft}

Now, let us put r = 4 in the formula of Surface Area to find the value of Surface Area:

Surface\ Area = 4\pi 4^2 = 4 \times 3 \times 16 = \bold{192\ ft^2}

So, approximate surface area of sculpture is 192 ft^2.

3 0
3 years ago
How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the
miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

<h3>8d.</h3>

\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}

___

<h3>9b.</h3>

\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}

___

<h3>10b.</h3>

\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}

Neither solution makes any denominator be zero, so both are good solutions.

8 0
3 years ago
Rectangle ABCD has vertices A(8,5), B(8,10), C(14,10), and D(14,5). A dilation with a scale factor of 1.2 and centered at the or
ycow [4]
Vertex A would be at (9.6, 6)
3 0
3 years ago
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