What is $526.36 rounded to the nearest 10 dollars?

Help please i got 3,800 but it says he walked home again help please :D

miskamm [114]

Answer:

I think you just add another 3 kilos

Step-by-step explanation:

3 kilos = 3000 meters

7 0

3 years ago

Tayler claims that when a linear equation is written in general form, Ax + By+ C = 0, the

Mumz [18]

Ax + By + C = 0
A. 3x + 5y + 45 = 0
3x + 5(0) + 45 = 0
3x = -45
x = -45/3......x int.....-C/A
x = -15

B. To find the x intercept, u must sub in 0 for y and solve for x

C. This is not true for a horizontal line because u can't sub in 0 for x because a horizontal line never crosses the x axis and therefore, does not have an x axis.

D. y int is -C/B....u find this by subbing in 0 for x and solving for y
3x + 5y + 45 = 0
3(0) + 5y + 45 = 0
5y = -45
y = -45/5......y int = -C/B
y = -9

8 0

3 years ago

Suppose that Y1, Y2,..., Yn denote a random sample of size n from a Poisson distribution with mean λ. Consider λˆ 1 = (Y1 + Y2)/

Burka [1]

Answer:

The answer is " $\bold{\frac{2}{n}}$ ".

Step-by-step explanation:

considering $Y_1, Y_2,........, Y_n$ signify a random Poisson distribution of the sample size of n which means is λ.

$E(Y_i)= \lambda \ \ \ \ \ and \ \ \ \ \ Var(Y_i)= \lambda$

Let assume that,

$\hat \lambda_i = \frac{Y_1+Y_2}{2}$

multiply the above value by Var on both sides:

$Var (\hat \lambda_1 )= Var(\frac{Y_1+Y_2}{2} )$

$=\frac{1}{4}(Var (Y_1)+Var (Y_2))\\\\=\frac{1}{4}(\lambda+\lambda)\\\\=\frac{1}{4}( 2\lambda)\\\\=\frac{\lambda}{2}\\$

now consider $\hat \lambda_2$ = $\bar Y$

$Var (\hat \lambda_2 )= Var(\bar Y )$

$=Var \{ \frac{\sum Y_i}{n}\}$

$=\frac{1}{n^2}\{\sum_{i}^{}Var(Y_i)\}\\\\=\frac{1}{n^2}\{ n \lambda \}\\\\=\frac{\lambda }{n}\\$

For calculating the efficiency divides the $\hat \lambda_1 \ \ \ and \ \ \ \hat \lambda_2$ value:

Formula:

$\bold{Efficiency = \frac{Var(\lambda_2)}{Var(\lambda_1)}}$

$=\frac{\frac{\lambda}{n}}{\frac{\lambda}{2}}\\\\= \frac{\lambda}{n} \times \frac {2} {\lambda}\\\\ \boxed{= \frac{2}{n}}$

8 0

3 years ago

Solve the linear system if 3x+4y-z=-6 5x+8y+2z=2. -x+y+z=0

Anni [7]

We are given with three equations and three unknowns and we need to solve this problem. The solution is shown below:
Three equations are below:
3x + 4y - z = -6
5x + 8y + 2z = 2
-x + y + z = 0

use the first (multiply by +2) and use the second equation:
2 (3x+4y -z = -6) => 6x + 8y -2z = -12
+ ( 5x + 8y +2z = 2)
------------------------
11x + 16y = -10 -> this the fourth equation

use the first and third equation:
3x + 4y -z = -6
+ (-x + y + z =0)
-------------------------
2x + 5y = -6 -> this is the fifth equaiton

use fourth (multiply by 2) and use fifth (multiply by -11) equations such as:
2 (11x + 16y = -10) => 22x + 32y = -20 -> this is the sixth equation
-11 (2x + 5y = -6) => -22x -55y = 46 -> this is the seventh equation

add 6th and 7th equation such as:
22x + 32y = -20
+(-22x - 55y = 66)
---------------------------
- 23y = 46
<span> y = -2

solving for x, we have:
</span>2x + 5y = -6
2x = -6 - 5y
2x = -6 - (5*(-2))
2x = -6 +10
2x = 4
x=2

solving for y value, we have:
-x + y + z =0
z = x -y
z = 2- (-2)
z =4

The answers are the following:
x = 2
y = -2
z = 4

5 0

4 years ago

Write {4, 16, 36, 64, 100, 144} in set builder notation

docker41 [41]

Answer:

Here we are given with the numbers 4 16 36 64 100

So in these kind of questions we have to find what common pattern is prevailing so in this one:

Subtracting every no from it's succeeding no gives a difference and those respective differences are forming pattern as follows:

16–4=12

36–16=20

64–36=28

100–64=36

So we have a new series 12 20 28 36 in this Subtracting every no from it's succeeding no gives a difference of 8 now in the latter series continues with the same pattern of difference of 8 and the series proceeds with next numbers 44 52 60 now these no gets added in the first original series as described as follows :

100+44=144

144+52=196

196+60=256

So the next 3 numbers are 144,196,256

5 0

3 years ago