The unit normal for the given plane is <5,2,-1>.
The equation of the plane parallel to the given plane passing through (5,5,4) is therefore
5(x-5)+2(y-5)-1(z-4)=0
simplify =>
5x+2y-z=25+10-4=31
Answer: the plane through (5,5,4) parallel to 5x+2y-z=-6 is 5x+2y-z=31
I believe the answer is -51+60 because it equals -9. And -51-(-60) is 9.
Answer:
C 
Step-by-step explanation:
Answer:
It is -4 :)
Step-by-step explanation:
I just did this lol
Answer:
-2
Step-by-step explanation:
Let x be the unknown value
Log₆ ( 1/36) = x
( 1/36) = 36⁻¹ = (6²)⁻¹ = 6⁻²
Log₆ ( 1/36) = Log₆
6⁻² = -2 Log₆
6
Log₆
6 = 1
-2 Log₆
6 = -2(1) = -2
