All categories

3 years ago

HELP ASAP!!!!! PLEASE

Mathematics

1 answer:

Eva8 [605]3 years ago

8 0

Find the area of the square, which has a side length of 2.

Area of square = 2 x 2 = 4

Now multiply the area by the length b

Volume = 4 x 5 = 20 square units total.

You might be interested in

Find the value of x and y

Yakvenalex [24]

Answer:

x = 80, y = 122

Step-by-step explanation:

I got this equation by using vertical angles to create a complimentary angle pair (they sum to 90 degrees).

3/4x+2/5x-2=90°,

23/20x - 2=90°,

23/20x = 92°,

92/(23/20)

20/(1/4)

20(4)

= 80.

Since the angles are a linear pair on the left side(they sum to 180 degrees). Just subtract 180 from 3/4x-2 and substitute x into the expression.

180-(3/4(x)-2), 180-3/4(80)+2 = 120+2 = 122

7 0

3 years ago

Read 2 more answers

How many 1/4 cup servings are in 4 cups of oatmeal ?

Wewaii [24]

4 1/4 cup servings
hope this helps

5 0

3 years ago

Read 2 more answers

Twice the quantity of 4d increased by 9 is 33.

slava [35]

play with my melons and drool my girl part

Step-by-step explanation:

it would feel so good and after i can make you com it will make you feel better

5 0

3 years ago

write an equation that describes the proportional relationship between the number of days in the number of weeks in a given leng

KatRina [158]

Answer:

Week 1 Day 7

Week 2 Day 14

Week 4 Day 28

Week 8 Day 56

Week 10 Day 70

Let x represent the number of weeks

Let y represent the number of days

Use the ratio of the constant of proportionally in the equation y =kx

y = 14/7x

y = 2x

Step-by-step explanation:

6 0

3 years ago

Harmonic mean if a number h such that (h-a)/(b-h)=a/b Prove h is H(a,b) iff satisfies either relation a. (1/a)-(1/h) = (1/h) - (

Fudgin [204]

A.

$\displaystyle\frac1a-\frac1h=\frac1h-\frac1b$
$\implies\displaystyle\frac{h-a}{ah}=\frac{b-h}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac{ah}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac ab$

b.

$\displaystyle h=\frac{2ab}{a+b}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{\frac{2ab}{a+b}-a}{b-\frac{2ab}{a+b}}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{2ab-a(a+b)}{b(a+b)-2ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{ab-a^2}{b^2-ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{a(b-a)}{b(b-a)}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac ab$

The other direction can be proved by following the manipulations in the reverse order.

7 0

3 years ago