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Softa [21]
3 years ago
7

HELP ASAP!!!!! PLEASE

Mathematics
1 answer:
Eva8 [605]3 years ago
8 0

Find the area of the square, which has a side length of 2.

Area of square = 2 x 2 = 4  

Now multiply the area by the length b

Volume = 4 x 5 = 20 square units total.

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HELP ME PLEASE BRAINLIEST ANSWER
Damm [24]

Answer:

D

Step-by-step explanation:

I'm not really 100% sure this is a weird question but I would assume D because if something is not proportional or doesn't conform to an equation, it has no slope

8 0
3 years ago
Which of these cannot represent the lengths of the sides of a right triangle?
Sholpan [36]
<h3>Answer: Choice D. 8m, 9m, 10m</h3>

==================================

Explanation:

If a = 8 and b = 9 are the two legs of a triangle and c = 10 is the hypotenuse, then

a^2 + b^2 = c^2

8^2 + 9^2 = 10^2

64 + 81 = 100

145 = 100

We get a false equation as 145 and 100 are two different values. So the original equation is false when (a,b,c) = (8,9,10)

By the converse of the pythagorean theorem, we have proven that this particular triangle is not a right triangle

-------------

Contrast this with something like choice A where we have a = 3, b = 4, c = 5 leading to

a^2 + b^2 = c^2

3^2 + 4^2 = 5^2

9 + 16 = 25

25 = 25

we get a true equation so a triangle with sides 3,4,5 is a right triangle. Choices B and C follow a similar path.

4 0
3 years ago
Read 2 more answers
Solve the system of equations below -3xy+6y=9
Tcecarenko [31]

Answer:

x=\frac{2y-3}{y}

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve the equation 2 sec² x = 3 - tan x for the domain 0° ≤ x ≤ 360° ​
vodka [1.7K]

2 \sec^2 x = 3- \tan x \\\\\implies 2(1 +\tan^2 x) = 3- \tan x \\\\\implies 2 + 2 \tan^2 x +\tan x -3 =0\\\\\implies 2 \tan^2 x + \tan x  -1 =0\\\\\implies 2u^2 + u -1 =0~~~ ;[\text{set} \tan x = u]\\\\\implies u = \dfrac{-1\pm \sqrt{1-4\cdot 2 \cdot (-1)}}{2(2)}\\\\\implies u =\dfrac{-1 \pm\sqrt{9}}{4}\\\\\implies u = \dfrac{-1 \pm 3}{4}\\\\\implies u = \dfrac{2}{4}=\dfrac 12~~ \text{or}  ~~u =\dfrac{-4}{4} =-1\\\\

\implies \tan x = \dfrac 12 ~~ \text{or} ~~  \tan x =-1~~~ ;[\text{Substitute back u =tan x}]\\\\\text{Now,}~ \\\\\tan x = -1,\\\\\implies x = n\pi - \dfrac{\pi}4\\\\\\\text{For interval,}~ [0,2\pi) \\\\x = \dfrac{3\pi}4, \dfrac{7\pi}4\\\\\text{In degrees,}~ x = 135^{\circ}, x =315^{\circ}\\\\\tan x = \dfrac 12\\\\\implies x = n\pi + \tan^{-1} \left(\dfrac 12 \right)\\\\\text{For interval} ~[0,2\pi),\\\\

x=\tan^{-1} \left(\dfrac 12 \right),  \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\text{in degrees,}   ~~x=\tan^{-1} \left(\dfrac 12 \right),  \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\\\\text{Combine all solutions:}\\\\x=\dfrac{3\pi}4, \dfrac{7\pi}4, \tan^{-1} \left(\dfrac 12 \right),  \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\

\text{In degrees,}~ x = 135^{\circ},~315^{\circ},~\tan^{-1} \left(\dfrac 12 \right),  \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]

4 0
2 years ago
PLEASE HELP!! will give brainliest
frutty [35]
A:
Table 1:
f(x) = 8x
X= cups so
ounces =
8* # of cups
Table 2:
f(x) =16x
X= pints so
ounces =
16*# of pints
Table 3:
f(x)= 32x
X= quarts so
ounces=
32*# of quarts
Note: another way instead of f(x)=kx is y=kx
B:
Depending on the slope we can easily find which is the steepest slope by easily comparing the slopes and seeing which is greater.
T1: 8
T2: 16
T3: 32
So, looking at our slopes, table 3 has the greatest slope because it has the greater slope out of the other two.
C:
The phrase, "rate of change" is another way to say the slope. To list again,
T1: 8
T2: 16
T3: 32
The table with the smallest slope would be table 1 since it is less than the other two tables.

I hope that helps, if you need any more assistance or you have any questions, please feel free to ask!!
6 0
3 years ago
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