The graph located in the upper right corner of the image attached shows the graph of y = 3[x]+1.
In order to solve this problem we have to evaluate the function y = 3[x] + 1 with a group of values.
With x = { -3, -2, -1, 0, 1, 2, 3}:
x = -3
y = 3[-3] + 1 = -9 + 1
y = -8
x = -2
y = 3[-2] + 1 = -6 + 1
y = -5
x = -1
y = 3[-1] + 1 = -3 + 1
y = -2
x = 0
y = 3[0] + 1 = 0 + 1
y = 1
x = 1
y = 3[1] + 1 = 3 + 1
y = 4
x = 2
y = 3[2] + 1 = 6 + 1
y = 7
x = 3
y = 3[3] + 1 = 9 + 1
y = 10
x y
-3 -8
-2 -5
-1 -2
0 1
1 4
2 7
3 10
The graph that shows the function y = 3[x] + 1 is the one located in the upper right corner of the image attached.
Answer:
33:100- 6:4- 5:3- 11/3
Step-by-step explanation:
First turn into even fractions
5:3= 1 2/3
6:4=1 1/2
11/3= 3 2/3
3/1= 3
33:100= 1/3
Then look at the numbers.
So pemdas
partneasees first ()
1+2=3
then dividsion multiplicatn wihciever comes first
6/2=3
3 times 3=9
answer is 9
Answer
Sorry! number 12 is 2
Step-by-step explanation:
Answer:
8) 10°
9) X can not be determined.
10) 10°
11) 12 units.
Step-by-step explanation:
8) The three sides of the given triangle are equal. Hence, the triangle is an equilateral triangle, hence each angle will be 60°.
So, 6x = 60°
⇒ x = 10°.
9) The three angles of the given triangle are equal. Hence, the triangle is an equilateral triangle, hence each side will be equal.
So, 6x - 5 = 6x
So, x can not be determined from this equation.
10) Δ KLM is equilateral, so, KN will bisect ∠ MKL. So, ∠ NKL = 30°
Hence, 3x = 30°
⇒ x = 10°
11) In Δ XYZ, XZ = XY , so, ∠ Z = ∠ Y.
Again, ∠ X is given to be 60°.
Therefore, each angle is 60°.
So, the triangle XYZ is equilateral, and each side will be equal.
So, 3x + 8 = 4x - 4
⇒ x = 12 units. (Answer)
