All categories

3 years ago

Equation. 1. h - 9= 2h - 1

2 answers:

8 0

H-9=2h-1
Add 9 to both sides
h-9+9=2h-1+9
h=2h+8
Subtract 2h from both sides
h-2h=2h+8-2h
-h=8
Divide both sides by-1
-h/-1=8/-1
h=-8 is your answer

lora16 [44]3 years ago

4 0

H= -8. H-2h= 9-1; -h=8; h= -8

You might be interested in

A coin is flipped 50 times and lands on heads 32 times. What is the experimental probability the coin will land on heads on the

oee [108]

D because if you do a rate problem you do 50 times what equals 100 so times two then you do 32 times two

4 0

3 years ago

Read 2 more answers

The lunch lady has 12 pounds of lasagna left over.

bogdanovich [222]

Answer:

Step-by-step explanation: if she has 12 pounds lasagna and make 1 pounds she can make 12 pounds for 12 people? hope this help you ;]

5 0

3 years ago

Are 4 7/9 and repeating 4.7 are they equal?

cluponka [151]

Answer:

Step-by-step explanation:

These two expressions are definitely not equal.

4 7/9 is a repeating decimal: 4.77777 ... (use your calculator)

whereqs 4.7 is NOT a repeating decimal.

4 0

3 years ago

The hypotenuse of a right triangle is three times the length of one of its legs. The length of the other leg is four feet. Find

andre [41]

Hello!

It is given information that this triangle is a right triangle, meaning that the Pythagorean Theorem can apply here.

$a^2+b^2=c^2$

We can set the length of a leg as an unknown variable $x$ .

$x^2+4^2=(3x)^2$

Remember that it is the whole $3x$ term being squared, meaning that it'll simplify to $9x^2$ , not $3x^2$ .

$x^2+16=9x^2$

$8x^2=16$

$x^2=2$

$x=\sqrt{2}$

This means we can plug back in to find the sides.

The hypotenuse would be $3\sqrt{2}$ , or 4.2.

And the legs would be 1.4 and 4, respectively.

Hope this helps!

7 0

2 years ago

A real estate agent has 14 properties that she shows. She feels that there is a 50% chance of selling any one property during a

Ratling [72]

Answer:

91.02% probability of selling more than 4 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The chance of selling any one property is independent of selling another property. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 14, p = 0.5$

Compute the probability of selling more than 4 properties in one week.

Either you sell 4 or less properties in one week, or you sell more. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 4) + P(X > 4) = 1$

We want to find $P(X > 4)$ . So

$P(X > 4) = 1 - P(X \leq 4)$

In which

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.5)^{0}.(0.5)^{14} = 0.000061$

$P(X = 1) = C_{14,1}.(0.5)^{1}.(0.5)^{13} = 0.000854$

$P(X = 2) = C_{14,2}.(0.5)^{2}.(0.5)^{12} = 0.0056$

$P(X = 3) = C_{14,3}.(0.5)^{3}.(0.5)^{11} = 0.0222$

$P(X = 4) = C_{14,4}.(0.5)^{4}.(0.5)^{10} = 0.0611$

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000061 + 0.000854 + 0.0056 + 0.0222 + 0.0611 = 0.0898$

Finally

$P(X > 4) = 1 - P(X \leq 4) = 1 - 0.0898 = 0.9102$

91.02% probability of selling more than 4 properties in one week.

8 0

3 years ago