If 0 < b ≤ 90 and cos(11b + 2) = sin(12b − 4), what is the value of b?
2 answers:
Answer:
b = 4
Step-by-step explanation:
The given expression is
Cos (11b + 2) = Sin (12b - 4)
Since, Sin(θ) = Cos(90 - θ)
Therefore, Cos (11b + 2) = Cos [90 - (12b - 4)]
Where 0 < b ≤ 90°
11b + 2 = 90 - (12b - 4)
11b + 2 = 94 - 12b
11b + 12b + 2 = 94 - 12b + 12b
11b + 12b + 2 - 2 = 94 - 2
23b = 92
b = 4
Therefore, b = 4 will be the answer.
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