Answer:
C
Step-by-step explanation:
(2x + 3)^5 = C(5,0)2x^5*3^0 +
C(5,1)2x^4*3^1 + C(5,2)2x^3*3^2 + C(5,3)2x^2*3^3 + C(5,4)2x^1*3^4 + C(5,5)2x^0*3^5
Recall that
C(n,r) = n! / (n-r)! r!
C(5,0) = 1
C(5,1) = 5
C(5,2) = 10
C(5,3) = 10
C(5,4) = 5
C(5,5) = 1
= 1(2x^5)1 + 5(2x^4)3 + 10(2x^3)3^2 + 10(2x^2)3^3 + 5(2x^1)3^4 + 1(2x^0)3^5
= 2x^5 + 15(2x^4) + 90(2x^3) + 270(2x^2) + 405(2x) +243
= 32x^5 + 15(16x^4) + 90(8x^3) + 270(4x^2) + 810x + 243
= 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243
The answer is no
Simplify 8/64= 1/8= 0.125
1/4= 0.25
= x1 + x2/2 , y1 + y2/2
= 7+-1/2 , 1+(-1)/2
Midpoint = (3,0)
Answer: C= -10
Step-by-step explanation: First step: simplify both sides of the equation
3c−2(c+10)=7c−5(c+2)
3c+(−2)(c)+(−2)(10)=7c+(−5)(c)+(−5)(2) (Distribute)
3c+−2c+−20=7c+−5c+−10
(3c+−2c)+(−20)=(7c+−5c)+(−10) (Combine Like Terms)
c + -20 = 2c - 10
c - 20 = 2c - 10
Step 2: Subtract 2c from both sides
c - 20 - 2c = 2c -10 - 2c
−c−20=−10
Step 3: Add 20 to both sides
−c−20+20=−10+20
−c=10
Step 4: Divide both sides by -1
-c/-1 = 10/-1
C=-10
Subtract 7 from both sides
x^2 - 6x - 7 = 7 - 7
Simplify
x^2 - 6x - 7 = 0
Answer :
The final solutions to the quadratic equation are:
x = 7, -1
