Question

If 0 < b ≤ 90 and cos(11b + 2) = sin(12b − 4), what is the value of b?

Answer 1

Answer:

b = 4

Step-by-step explanation:

The given expression is

Cos (11b + 2) = Sin (12b - 4)

Since, Sin(θ) = Cos(90 - θ)

Therefore, Cos (11b + 2) = Cos [90 - (12b - 4)]

Where 0 < b ≤ 90°

11b + 2 = 90 - (12b - 4)

11b + 2 = 94 - 12b

11b + 12b + 2 = 94 - 12b + 12b

11b + 12b + 2 - 2 = 94 - 2

23b = 92

$\frac{23b}{23}=\frac{92}{23}$

b = 4

Therefore, b = 4 will be the answer.

Answer 2

Answer: B=4

Step-by-step explanation: Took the test for my geometry class