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3 years ago

Write an addition equation or a subtraction equation to describe the diagram

Mathematics

1 answer:

Blababa [14]3 years ago

3 0

Answer:

add the diagram

Step-by-step explanation:

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A manager wants to build 3-sigma x-bar control limits for a process. The target value for the mean of the process is 10 units

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Answer:

Step-by-step explanation:

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3 years ago

Which number line represents the solution set for inequality?

AlekseyPX

Answer:

Third graph down

Step-by-step explanation:

2x -6 ≥ 6(x-2)+8

Distribute

2x - 6≥6x -12+8

Combine like terms

2x - 6≥6x -4

Subtract 2x from each side

2x-6-2x ≥6x-2x-4

-6 ≥4x-12

Add 4 to each side

-6+4 ≥4x-4+4

-2 ≥4x

Divide by 4

-2/4 ≥4x/4

-1/2≥x

Closed circle at -1/2

Line going the the left

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3 years ago

One day at 3:00 a.m., the temperture was -13 degrees F in Kodiak ,Alaska. At 10:00 a.m. the temperature was 22 degrees F. what w

Ksju [112]

The average change in temperature is +5 degrees every 1 hour.

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3 years ago

Read 2 more answers

Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.

sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

$\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ · X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ =I.

First, we have to identify the matrix I. As it was said, the matrix is the identiy matrix, which means

I = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

So, $\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ · X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Isolating the X, we have

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ - $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Resolving:

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]$

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X= $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ ⁻¹· $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

$\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ · $\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]$ = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a= $\frac{2}{11}$ ; b= $\frac{7}{33}$ ; c= $\frac{-1}{11}$ and d= $\frac{-3}{11}$ . Substituting:

X= $\left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11} \end{array}\right]$ · $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Multiplying the matrices, we have

X= $\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11} \end{array}\right]$

6 0

3 years ago

triangle abc has vertices at a(-2 3),B(0,3),c(-1,-1). Find the coordinates of the image after a reflection over the x-axis.

Crazy boy [7]

The new coordinates of the triangle after reflection from x-axis would be A(-2, -3) , B(0, -3) and C( -1, 1 )

Explanation:

The vertices of the triangle are A(-2 3), B(0,3), C(-1,-1)

The reflection is over the x-axis.

When the reflection is along the x-axis, the coordinates of x does not change. However, the coordinates of y does change.

The negative value of y becomes positive and the positive value of y becomes negative.

Similarly,

A(-2, 3) would become A(-2, -3)

B(0, 3) would become B(0, -3)

C(-1, -1) would become C( -1, 1 )

Therefore, the new coordinates of the triangle after reflection from x-axis would be A(-2, -3) , B(0, -3) and C( -1, 1 )

6 0

4 years ago