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3 years ago

Does (–2, 0) make the equation y = x true?

Mathematics

1 answer:

WINSTONCH [101]3 years ago

3 0

No. y=x would mean it would either be (-2,-2) or (0,0). basically they have to be the same.

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What is the distance between (4,2) and (-1,-3)

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<h2>Solving for the Distance between two Points</h2><h3>Answer:</h3>

$5 \sqrt{2}$ or $7.071$

<h3>Step-by-step explanation:</h3>

<em>Please refer to my answer from this Question to know more about distances between two points: <u>brainly.com/question/24629826</u></em>

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Solving for the Distance:

$\sqrt{(4-(-1))^2 +(2 -(-3))^2} \\ \sqrt{(4 +1)^2 +(2 +3)^2} \\ \sqrt{5^2 +5^2} \\ \sqrt{25 +25} \\ \sqrt{50} \\ \sqrt{25 \cdot 2} \\ 5 \sqrt{2}$

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$5 \sqrt{2} \approx 7.071$

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The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. (a) Determine the

maxonik [38]

Answer:

a) 0.5 = 50% of flanges exceed 1 millimeter.

b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

$P(X > x) = \frac{b - x}{b - a}$

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

This means that $a = 0.95, b = 1.05$

(a) Determine the proportion of flanges that exceeds 1.00 millimeters.

$P(X > 1) = \frac{1.05 - 1}{1.05 - 0.95} = \frac{0.05}{0.1} = 0.5$

0.5 = 50% of flanges exceed 1 millimeter.

(b) What thickness is exceeded by 90% of the flanges?

This is x for which:

$P(X > x) = 0.9$

$\frac{1.05 - x}{1.05 - 0.95} = 0.9$

$1.05 - x = 0.9*0.1$

$x = 1.05 - 0.9*0.1$

$x = 0.96$

A thickness of 0.96 millimeters is exceeded by 90% of the flanges

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3 years ago