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Anestetic [448]

3 years ago

12

A swimming pool in the shape of a right rectangular prism measures 24 feet by 16 feet and is 4.5 feet deep across the entire poo

l. What is the volume of the swimming pool, in cubic feet?
72
108
324
1,728

2 answers:

aalyn [17]3 years ago

8 0

Answer: D- 1,728

Step-by-step explanation: I did the quiz

goblinko [34]3 years ago

4 0

Answer:

d

Step-by-step explanation:

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If you needed only 1 c of milk, what is your best choice at the grocery store? a quart container, a pint container, or a 1/2 gal

Lena [83]

What would be best to buy is the quart container

8 0

4 years ago

Find the area of the shaded region.

luda_lava [24]

Answer:

The area of the shaded region is $11.6\ cm^{2}$

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the sector of circle of angle 68.9 degrees minus the area of the isosceles triangle

step 1

Find the area of sector of the circle

The area of circle is equal to

$A=\pi r^{2}$

assume

$\pi =3.14$

$r=9.28\ cm$

substitute

$A=(3.14)(9.28)^{2}$

$A=270.41\ cm^{2}$

Remember that the area of a circle subtends a central angle of 360 degrees

so

using proportion Find out the area of a sector with a central angle of 68.90 degrees

Let

x -----> the area of a sector

$270.41/360=x/68.90\\\\x=68.90*270.41/360\\\\x=51.75\ cm^{2}$

step 2

Find the area of the isosceles triangle

Applying the law of sines

The area is equal to

$A=(1/2)r^{2}sin(68.90)$

we have

$r=9.28\ cm$

substitute

$A=(1/2)(9.28)^{2}sin(68.90)=40.17\ cm^{2}$

step 3

Find the area of the shaded region

$51.75-40.17=11.58\ cm^{2}$

Round to the nearest tenth

$11.58=11.6\ cm^{2}$

3 0

4 years ago

What is the solution of 5w + 12= 67

Gnom [1K]

5w+12=67
-12 -12
5w=55
w=11

first, subtract 12 from both sides. second, divide 5 on both sides

7 0

3 years ago

Read 2 more answers

In a G.P., the third term exceeds the first term by 16.

Tresset [83]

Answer:

Step-by-step explanation:

In a G.P, the nth term is given as

Un=ar^(n-1)

Where

a is first term

n is nth term

And r is common ratio

So in the question given above,

The third term exceed the first term by 16

i.e U3=U1+16

Where U1=a. First term

U3=a+16

Given also that, the sum if the third term and fourth term is 72.

Then U3+U4=72.

We are told to find common ratio (r)

U3=ar^3-1

U3=ar^2

Also, U4=ar^3

U3+U4=72

ar^2+ar^3=72

ar^2(1+r)=72. equation 1

Also for

U3=a+16

ar^2=a+16

ar^2-a=16

a(r^2-1)=16. From (x^2-y^2)=(x+y)(x-y)

Then,

a(r-1)(r+1)=16. Equation 2

Divide equation 2 by equation 1

a(r-1)(r+1)/ar^2(1+r) =16/72

Then a cancel a and (1+r) cancel (1+r)

So,

(r-1)/r^2=2/9

Cross multiply

9(r-1)=2r^2

2r^2-9r+9=0

Solving the quadratic equation

2r^2-6r-3r+9=0

2r(r-3)-3(r-3)=0

(r-3)(2r-3)=0

r-3=0. Or. 2r-3= 0

Then r=3 or r=3/2

8 0

3 years ago

Order each set of numbers from greatest to least square root 43, 3.6, -3 square root 2?

Alekssandra [29.7K]

√(43) = 6.55.
-3√(2) = -4.24...

√(43) > 3.6 > -3√(2)

4 0

4 years ago