Show that if p(a) ⊂ p(b) then a ⊂ b.
<span>I will assume p() means power set. </span>
<span>proof: let x∈a, then {x} ∈ p(a) and so by hypothesis {x} ∈ p(b). However {x} could not be in p(b) unless x∈b. This shows that each element of a is an element of b and hence a ⊂ b.
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Answer: ∠A ≅ ∠A; reflexive property
Step-by-step explanation: found it online :)
Given:
64 total students
x = drama club students
y = yearbook club students
x = y + 10
y = 64 - x
y = 64 - x
y = 64 - (y + 10)
y = 64 - y - 10
y + y = 64 - 10
2y = 54
2y/2 = 54/2
y = 27
x = y + 10
x = 27 + 10
x = 37
To check:
x + y = 64
37 + 27 = 64
64 = 64
Answer:
x = ±i(√6 / 2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
<u>Algebra II</u>
Imaginary root i
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
2x² + 3 = 0
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Subtraction Property of Equality] Subtract 3 on both sides: 2x² = -3
- [Division Property of Equality] Divide 2 on both sides: x² = -3/2
- [Equality Property] Square root both sides: x = ±√(-3/2)
- Simplify: x = ±i(√6 / 2)
