<img src="https://tex.z-dn.net/?f=%20-%206x%20%2B%205%20%5Cgeqslant%2011" id="TexFormula1" title="

All categories

Dimas [21]

3 years ago

- 6x + 5 \geqslant 11" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Lesechka [4]3 years ago

7 0

Answer:

Step-by-step explanation:

-6x + 5 ≥ 11

-6x ≥ 6

x ≤ -1

You might be interested in

Jim walks 2 miles in an hour. It takes him 3 hrs to walk 6 miles.

pentagon [3]

Answer:

He would walk 10 miles in 5 hours, and it would take him 2 hours to walk 4 miles.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the surface area of this right rectangular prism with dimensions of 4 centimeters by 4 centimeters by 6 centimeters?

bagirrra123 [75]

Answer:

Step-by-step explanation:

This is because using the formula of area for shapes, you get this equation

A=2(wl+hl+hw)=2·(4·6+4·6+4·4)=128

7 0

3 years ago

Read 2 more answers

Define fn : [0,1] --> R by the

sasho [114]

Answer:

The sequence of functions $\{x^{n}\}_{n\in \mathbb{N}}$ converges to the function

$f(x)=\begin{cases}0&0\leq x$ .

Step-by-step explanation:

The limit $\lim_{n\to \infty }c^{n}$ exists and converges to zero whenever $\lvert c \rvert$ . But, if $c=1$ the sequence $\{c^{n}\}$ is constant and all its terms are equal to $1$ , then converges to $1$ . Using this result, consider the sequence of functions $\{f_{n}\}$ defined on the interval $[0,1]$ by $f_{n}(x)=x^{n}$ . Then, for all $0\leq x$ we have that $\lim_{n\to \infty}x^{n}=0$ . Now, if $x=1$ , then $\lim_{n\to \infty }x^{n}=1$ . Therefore, the limit function of the sequence of functions is