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fenix001 [56]
3 years ago
14

Define a variable, write an equation and SOLVE the equation. Sandy had

Mathematics
2 answers:
Mrrafil [7]3 years ago
8 0
21 dollars each because 189 divided by 9 is 21
notka56 [123]3 years ago
7 0
The answer is 21 because 189 divided by 9 is 21
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2.5 in

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Help please! If you help I will give brainliest! Do BOTH of the images.
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What is the measure of angle SQR?​
Mademuasel [1]

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Step-by-step explanation:

6x +4x = 180

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Katyanochek1 [597]

Write tan in terms of sin and cos.

\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}

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\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1

Rewrite and expand the given limand as the product

\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)

Then using the known limit above, it follows that

\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}

4 0
2 years ago
Can somebody help me?????
natta225 [31]

Answer:

1/2 = 3/6

Step-by-step explanation:

.................

6 0
3 years ago
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