Answer:
(a-b-c)(a-b+c)
Step-by-step explanation:
a^2-2ab+b^2-c^2
(a-b)^2-c^2
(a-b-c)(a-b+c)
Answer: C. 3, 11, 23, 31
Step-by-step explanation:
None of these can be divided by anything except themselves and 1.
Yes, find the prime factors.
4 can be written as 2*2.
g^4 can be written as g*g*g*g.
That is the prime factorization of the first expression.
4g^4 can be written as 2*2*g*g*g*g.
34 can be written as 2*17.
And again we can split up the g business: g^3 is g*g*g.
34g^3 can be written as 2*17*g*g*g.
What do these expressions have in common?
They have a 2 in common,
and three of the g's in common, ya?
Therefore the GCF(4g^4, 34g^3) = 2g^3.
❀ 
To solve, use the algebraic identity ➺
- <u>(x + a)( x + b) = x² + (a + b)x + ab</u>
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐
Answer is y= 1/2x+1
One method is first substituting x=4,y=3 and next once again substituting x=y=2
