To subtract 7 from 102, you have to regroup. You subtract 2 from 100, and 2 from 7, so it is 100-5. 100-5 is 95. The answer is 95. If you don't understand, tell me in the comments. This is just one method of subtracting.
<span>D. L.A. to Flagstaff, 465 miles; Flagstaff to Albuquerque, 345 miles
The answer above is correct.
810 - 120 = 690 ; 690 / 2 = 345 mi ( Flagstaff to Albuquerque )
810 - 345 = 465 mi ( L.A. to Flagstaff )
</span>
Answer:
Step-by-step explanation:
3 and 2/5
(aka A)
Using squares of integers numbers, it is found that the solution of the equation is located between the integers x = 1 and x = 2.
The equation given is:
The solution of the equation given is:
The squares of the integers numbers until the square root of 3 are:
Since 
, the square root of 3, which is the solution to the equation, is located between the integers x = 1 and x = 2.
A similar problem is given at brainly.com/question/3729492
Answer:
Sticks of butter : 2
Number of cookies : 40
Step-by-step explanation:
<em>Given that :You need 3 sticks of butter for every 24 giant cookies you bake.</em>
<em>----------------------------------------------------------------------------------------------------------</em>
<em>Sticks of butter Number of cookies</em>
<em> 3 24</em>
<em> x 16</em>
<em>5 y</em>
<em>----------------------------------------------------------------------------------------------------------</em>
<em>Let the unknown be x and y..</em>
<em>Since you need 3 sticks of butter for every 24 giant cookies you back</em>
<em>Then 24/3 = 8</em>
<em>Since the number of cookies is 16 then 16/8 = 2</em>
<em>Thus x = 2</em>
<em>Next for y.</em>
<em>Since you need 3 sticks of butter for every 24 giant cookies you back</em>
<em>Then 5 * 8 = 40</em>
<em>Thus, y = 40</em>
<em>----------------------------------------------------------------------------------------------------------</em>
<em>Completed table below:</em>
<em>Sticks of butter Number of cookies</em>
<em> 3 24</em>
2 <em> 16</em>
<em>5 </em><em>40</em>
<em>----------------------------------------------------------------------------------------------------------</em>
<u><em>~lenvy~</em></u>
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