Step-by-step explanation:
tan⁻¹(x) = ∑ₙ₌₀°° (-1)ⁿ x²ⁿ⁺¹ / (2n+1)
tan⁻¹(1/√3) = ∑ₙ₌₀°° (-1)ⁿ (1/√3)²ⁿ⁺¹ / (2n+1)
tan⁻¹(1/√3) = ∑ₙ₌₀°° (-1)ⁿ (1/√3) (1/√3)²ⁿ / (2n+1)
tan⁻¹(1/√3) = (1/√3) ∑ₙ₌₀°° (-1)ⁿ (1/3)ⁿ / (2n+1)
π/6 = (1/√3) ∑ₙ₌₀°° (-1)ⁿ (1/3)ⁿ / (2n+1)
π = (6/√3) ∑ₙ₌₀°° (-1)ⁿ (1/3)ⁿ / (2n+1)
π = 2√3 ∑ₙ₌₀°° (-1)ⁿ / (3ⁿ (2n+1))
Answer:
Its A on edge
The modulus increases by a factor of 216, and the argument increases by StartFraction pi Over 2 EndFraction.
Step-by-step explanation:
Step-by-step explanation:
we know that
Work =f*d
=25*100
=2500Joule
therefore work done is 2500Joule
