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Ilia_Sergeevich [38]
3 years ago
10

What is the lowest value of the range of the function shown on the graph? 0 3

Mathematics
2 answers:
erik [133]3 years ago
5 0

Answer:

-1 -2 -3 -4 -5 -6 -7 -8 -9 -10 1:2

strojnjashka [21]3 years ago
4 0

Answer:

-2

Step-by-step explanation:

Edge 2020

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What is the length (magnitude) of the vector (5 -2) <br> a. √29<br> b. 5√5<br> c. 5<br> d.√2
malfutka [58]

Answer:

a. √29

Step-by-step explanation:

The formula for the magnitude of a vector is magnitude = sqrt(x^2 + y^2).

For vector (5, -2):

magnitude = sqrt(5^2 + -2^2)

magnitude = sqrt(25 + 4)

magnitude = sqrt(29)

Therefore, the answer is √29.

Hope this helped :D

8 0
3 years ago
Solve the equation: x2 = 1
oee [108]

Answer:

x = 0.5

Step-by-step explanation:

hope this helps!

3 0
3 years ago
Read 2 more answers
Graham paid $87.45 for a pair of jeans. This amount included a tax of 40%. What was the cost of the jeans before tax?
kiruha [24]

The final price is the cost plus the tax.

Since we know the tax and a percent, we can write this as

T = C(1+r)

T = what Graham paid = $87.45

C = cost before tax

r = tax rate expressed as a decimal = .40

Plugging in what we know

87.45 = C (1+.4)

87.45 = C(1.4)

Divide both sides by 1.4

C = $62.46

5 0
3 years ago
Three times the difference of four times a number n and seven is no more than one
Sindrei [870]

Answer:

3x-4x7

Step-by-step explanation:

8 0
2 years ago
66 points! for if you get this right 99 kids go race go karts for a all day pass is $56 per kid then they play arcade games at a
Romashka-Z-Leto [24]

The total amount that was spent is $6099

<h3>How to determine the total amount that was spent?</h3>

The given parameters are

Number of kids = 99

Pass = $56 per kid

Arcade game = $555

The total amount that was spent is calculated as

Total = Number of kids * Pass + Arcade game

So, we have

Total = 99 * 56 + 555

Evaluate the expression

Total = 6099

Hence, the total amount that was spent is $6099

Read more about expressions at

brainly.com/question/723406

#SPJ1

7 0
1 year ago
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