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VMariaS [17]
3 years ago
12

NEED HELP FAST!!! 25 POINTS!

Mathematics
1 answer:
Yuki888 [10]3 years ago
5 0

Answer:

0.55

Step-by-step explanation:

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tyler swims at constant speed, 5 meters every 4 seconds. how long does it take him to swim 114 meters?​
zysi [14]

28.5 seconds

cuz 114 ÷ 4 = 28.5 = 28.5 × 4 = 28.5

hope it will help u

3 0
3 years ago
Read 2 more answers
Please help!!!!!!!!!!!!!!!!
____ [38]

Answer:

  (i) x° = 28°

  (ii) y° = 104°

  (iii) z° = 76°

Step-by-step explanation:

x° is an alternate interior angle where transversal PQ crosses the parallel lines, so it has the same measure as the one marked 28°.

  x° = 28°

__

The base angles of isosceles triangle PQR are both z°, so we must have ...

  z° +z° +28° = 180° . . . . . . . . . sum of angles in a triangle

  z° = (180° -28°)/2 = 152°/2 . . . solve for z

  z° = 76°

__

y° and z° are a linear pair, so ...

  y° = 180° -76°

  y° = 104°

5 0
2 years ago
Use vertical multiplication to find the product of:
Rom4ik [11]

Answer:

x^6+x^4+4x^3-2x^2-x+3

Step-by-step explanation:

x^3+2x+3

\times(x^3-x+1)

---------------------------------

First step multiply your terms in your first expression just to the 1 in the second expression like so:

x^3+2x+3

\times(x^3-x+1)

---------------------------------

x^3+2x+3  Anything times 1 is that anything.

That is, (x^3+2x+3) \cdot 1=x^3+2x+3.

Now we are going to take the top expression and multiply it to the -x in the second expression. -x(x^3+2x+3)=-x^4-2x^2-3x.  We are going to put this product right under our previous product.

x^3+2x+3

\times(x^3-x+1)

---------------------------------

x^3+2x+3

-x^4-2x^2-3x  

We still have one more multiplication but before we do that I'm going to put some 0 place holders in and get my like terms lined up for the later addition:

x^3+2x+3

\times(x^3-x+1)

---------------------------------

0x^4+x^3+0x^2+2x+3

-x^4+0x^3-2x^2-3x+0  

Now for the last multiplication, we are going to take the top expression and multiply it to x^3 giving us x^3(x^3+2x+3)=x^6+2x^4+3x^3. (I'm going to put this product underneath our other 2 products):

x^3+2x+3

\times(x^3-x+1)

---------------------------------

0x^4+x^3+0x^2+2x+3

-x^4+0x^3-2x^2-3x+0  

x^6+2x^4+3x^3

I'm going to again insert some zero placeholders to help me line up my like terms for the addition.

x^3+2x+3

\times(x^3-x+1)

---------------------------------

0x^6+0x^4+x^3+0x^2+2x+3

0x^6-x^4+0x^3-2x^2-3x+0  

x^6+2x^4+3x^3+0x^2+0x+0

----------------------------------------------------Adding the three products!

x^6+x^4+4x^3-2x^2-x+3

8 0
4 years ago
Help if you can thank you
Archy [21]

But I can't see any question here......?

3 0
3 years ago
Read 2 more answers
PLEASE HELP !! I NEED HELP ASAP?
Daniel [21]

Answer:

The answer would be D or 4 or whatever you would like to call it (the bottom one)

4 0
3 years ago
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