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vladimir1956 [14]
3 years ago
13

What is the greatest common factor of 60, 45 and 82? HALPPPPPPPPPPPPPPPPPPp

Mathematics
2 answers:
son4ous [18]3 years ago
4 0

Answer:

GCF: 1

Step-by-step explanation:

Factors are numbers that can be evenly divided into another number. The greatest common factor of a set of numbers is the biggest number than can evenly divide into all the the numbers.

Let's list the factors of 60, 45 and 82

Factors of 60:

<u>1</u>, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

Factors of 45:

<u>1</u>, 3, 5, 9, 15, 45

Factors of 82:

<u>1</u>, 2, 41, 82

The greatest factor that all 3 numbers share is 1.

enot [183]3 years ago
3 0

The right answer is 1.

Please see the attached picture for full solution

Hope it helps

Good luck on your assignment..

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This is a simple equation:

x - 7 < 14

x < 14 + 7

x < 21

→ Many people think that because there is not "=" sign they don't flip the sign of what in this case is -7. But actually, the symbols "<" and ">" act as the equal sign. This rule doesn't apply to positive number, only negative.


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BioTeacher101


(If you have any questions, feel free to ask them in the comments)

6 0
3 years ago
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2. Which of these describes a unique polygon?
dimulka [17.4K]

Answer: A

Step-by-step explanation:

6 0
4 years ago
The original price of a coat is $90. It is on sale for 20% off. How much will you pay if you buy the cost during the sale?
ziro4ka [17]

Answer:

72$

Step-by-step explanation

How to insert in a calculator 90-20%= 72

How to take 20% from a price

Divide the original price by 5. <em>18</em>

Subtract this new number from the original one. <em>90 - 18 </em>

The number you calculated is the discounted value. <em>90 - 18 = </em><u><em>72</em></u>

6 0
3 years ago
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In 1998, Cathy's age is equal to the sum of the four digits in the year of her birthday, then how old was Cathy in 1998?
ycow [4]

Answer:

<em>Cathy was born in 1980 and she was 18 years old in 1998</em>

Step-by-step explanation:

<u>Equations</u>

This is a special type of equations where all the unknowns must be integers and limited to a range [0,9] because they are the digits of a number.

Let's say Cathy was born in the year x formed by the ordered digits abcd. A number expressed by its digits can be calculated as

x=1000a+100b+10c+d

In 1998, Cathy's age was

1998-(1000a+100b+10c+d)

And it must be equal to the sum of the four digits

1998-(1000a+100b+10c+d)=a+b+c+d

Rearranging

1998=1001a+101b+11c+2d

We are sure a=1, b=9 because Cathy's age is limited to having been born in the same century and millennium. Thus

1998=1001+909+11c+2d

Operating

88=11c+2d

If now we try some values for c we notice there is only one possible valid combination, since c and d must be integers in the range [0,9]

c=8, d=0

Thus, Cathy was born in 1980 and she was 18 years old in 1998. Note that 1+9+8+0=18

5 0
4 years ago
I need help with this answer?
Bumek [7]

Answer:

dont u have the answer

Step-by-step explanation:

7 0
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