Question

Which statement is true about the extreme value of the given quadratic equation? A. The equation has a maximum value with a y-coordinate of -21. B. The equation has a maximum value with a y-coordinate of -27. C. The equation has a minimum value with a y-coordinate of -21. D. The equation has a minimum value with a y-coordinate of -27.

Answer 1

Answer:

A. The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

From the given equation:

$\mathbf{y = -3x^2 + 12x -33}$

This parabola is vertical and is goes downward via the negative path

Where the vertex represents the maximum value;

$\mathbf{y = -3 (x^2 + 4x) -33}$

Using completing the square method;

$\mathbf{y = -3 (x^2 + 4x+2^2) -33+12}$

$\mathbf{y = -3 (x^2 + 4x+4) -21}$

To perfect square:

$\mathbf{y = -3 (x-2)^2 -21}$

The vertex point is (2, -21)

Hence ; the equation has a maximum value with a y-coordinate of -21.