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Serhud [2]
3 years ago
8

Which is easier to use - the outer semi-circle or the inner semi-circle?

Mathematics
1 answer:
AURORKA [14]3 years ago
6 0

Answer: the inner semi circle

Step-by-step explanation:

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GEOMETRY QUESTION PLEASE HELP
stiv31 [10]

Answer:

That is correct..good job! :D

Step-by-step explanation:

6 0
2 years ago
Evaluate the expression for the given value 3a^2 + 6b^3. a=3 b=2​
steposvetlana [31]

Answer:

5. is the answer

Step-by-step explanation:

5 0
3 years ago
The theoretical probability of landing on blue on a single spin of a spinner with 1 purple, 1 blue , 1 red , and 1 orange sectio
erik [133]

Hey there!

\large\boxed{25\%}

Assuming that all the sections are the same size, there are four sections of equal size.

Blue would be one out of those four sections, so the probability is 1/4. In decimal form this is .25, and as a percent this is 25%.

Hope this helps!

5 0
3 years ago
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When you dilate a figure by a factor of 2, which of the following statements are true? *
Drupady [299]

Answer:

it's c

Step-by-step explanation:

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6 0
3 years ago
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There are four movies showing at the theater, 2/5 of the people bought tickets for the comedy, 1/4 bought tickets for the horror
RUDIKE [14]

Given:

Number of people bought tickets for comedy = \frac{2}{5}

Number of people bought tickets for horror = \frac{1}{4}

Number of people bought tickets for kids movie = \frac{3}{10}

To find the number of people who bought tickets for the action movie.

Let us take,

Total number of tickets = 1

Now,

Total number of tickets for comedy, horror and kids movie are = (\frac{2}{5} +\frac{1}{4} +\frac{3}{10} )

So,

(\frac{2}{5} +\frac{1}{4} +\frac{3}{10} )

LCM of 5,4,10 = 20

= \frac{8+5+6}{20}

= \frac{19}{20}

Rest are action movie's tickets.

Therefore,

Number of action movie tickets = 1-\frac{19}{20}

= \frac{20-19}{20}

= \frac{1}{20}

Hence,

The number of people who bought the tickets for action movie is \frac{1}{20}.

7 0
3 years ago
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