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2 years ago

Hey can you guys help me with this? thx a lot! <3

Mathematics

1 answer:

iris [78.8K]2 years ago

3 0

Answer:

add x

Step-by-step explanation:

get the constants on one side, and the variables on the other for easiest solving.

You might be interested in

Find each measure m<1, m<2,m<3

Leno4ka [110]

Answer:

option 2.

m1 = 75 , m2 = 129 , m3 = 100

Step-by-step explanation:

with the rule that the internal angles of a triangle add up to 180 ° we can calculate the missing angles

x + 46 + 29 = 180

x = 180 - 46 -29

x = 105

a flat angle has 180 °

m1 + 105 = 180

m1 = 180 - 105

m1 = 75

46 + 54 + y = 180

y = 180 - 46 -54

y = 80

80 = z + 29

z = 80 - 29

z = 51

as they are two crossed lines the angle is reflected from the opposite side

with that principle and knowing that the angle of a turn is 360 °, if we subtract the 2 known angles and divide it by 2 we will obtain the missing angle (m2)

m2 * 2 = 360 - 51 * 2

m2 = 258/2

m2 = 129

m2 = 29 + m3

129 = 29 + m3

m3 = 129 - 29

m3 = 100

4 0

3 years ago

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$