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3 years ago

400 people are asked if they drink tea

Mathematics

1 answer:

Korvikt [17]3 years ago

5 0

Answer:

56 people drink 3 cups daily

Step-by-step explanation:

What's the total number of people that drink 3 cups?

Total number of people = 400

7 / 10 were asked said yes

Number of people that said yes = (7 / 10) × 400 = 280

280 people drink tea.

20% of 280 people drink 3 cups daily, whats the number = ?

20% of 280 = ?

20 / 100 = x / 280

(20 × 280) = (100 × x)

5600 = 100x

X = 5600 / 100

X = 56 people

56 people drink 3 cups of tea daily.

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Answer: $\frac{3}{10}$ of the mural is sky blue.

Step-by-step explanation:

Let x be the full portion of mural.

Since, $\frac{4}{5}$ of mural is painted in shades of blue.

Therefore, the blue portion= $\frac{4}{5}x$

Also, Three eighths of the blue area is sky blue.

Therefore, the portion of the mural is sky blue= $\frac{3}{8}\times\frac{4}{5}x$

The portion of the mural is sky blue= $\frac{12}{40}x$

Simplify, by dividing numerator and denominator by 4, we get

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3 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

The kinetic energy (K) that an object has varies jointly with its mass (m) and the square of its velocity (v). The equation that

lord [1]

The kinetic energy of the bowling ball with the mass and traveling at the given velocity is 10.14 Joules.

<h3>What is Kinetic Energy?</h3>

Kinetic energy is simply a form of energy a particle or object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Given that;

Mass of the bowling ball m = 3kg

Velocity of the bowling ball v = 2.6m/s

Kinetic energy K = ?

We substitute the given values into the above equation.

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2 years ago

In this exercise, T: R2 → R2 is a function. For each of the following parts, state why T is not linear. (a) T(a1, a2)= (1, a2) (

DENIUS [597]

Answer:

a) T is not homogeneous
b) T is not additive
c) T is not homogeneous
d) T is not additive
e) T is not additive

Step-by-step explanation:

In each case there is an example where one property of linear functions fails.

a) $T(2(1,0))=T((2,0))=(1,0); 2T((1,0))=2(1,0)=(2,0)$ . These vectors are not equal, then T doesn't satisfy the condition of scalar multiplication (homogeneity).

b) $T((1,2)+(2,3))=T(3,5)=(3,9); T((1,2))+T((2,3))=(1,1)+(2,4)=(3,5)$ . Because these vectors are not equal, T doesn't satisfy the property of vector addition (additivity).

c) $T(\frac{1}{2}(\pi,0))=T((\frac{\pi}{2},0))=(\sin(\frac{\pi}{2}),0)=(1,0); \frac{1}{2}T((\pi,0))=\frac{1}{2}(0,0)=(0,0)$ so T is not homogeneous.

d) $T((-1,0)+(1,0))=T(0,0)=(0,0); T((-1,0))+T((1,0))=(1,0)+(1,0)=(2,0)$ then T is not additive.

e) $T((0,0)+(1,0))=T(1,0)=(2,0); T((0,0))+T((1,0))=(1,0)+(2,0)=(3,0)$ then T is not additive.

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3 years ago