Answer: There will enough to paint the outside of a typical spherical water tower.
Step-by-step explanation:
1. Solve for the radius r from the formula for calculate the volume of a sphere. as following:
2. Substitute values:
3. Substitute the value of the radius into the equation fo calculate the surface area of a sphere, then you obtain that the surface area of a typical spherical water tower is:
3. If a city has 25 gallons of paint available and one gallon of paint covers 400 square feet of surface area, you must multiply 25 by 400 square feet to know if there will be enough to paint the outside of a typical spherical water tower.
As you can see, there will enough to paint the outside of a typical spherical water tower.
Answer:
bob got six
Step-by-step explanation:
Answer:
B. x > 3
Step-by-step explanation:
Well we first simplify the following inequality,
3(8 - 4x) < 6(x - 5)
Distribute
24 - 12x < 6x - 30
Communicative property
-6x
24 - 18x < -30
-24
-18x < -54
Divide -18x by both sides
Which flips the < to a >.
x > 3
<em>Thus,</em>
<em>the answer is B. x > 3.</em>
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<em>Hope this helps :)</em>
Answer: The answer is C) 44 units.
Step-by-step explanation:
The question is asking for perimeter, not area. Instead of multiplying 9*13 to get area, we need to add the sides together. If the width on one side is 13, so is the witdh on the other side. This rule applies to the length as well.
9 + 9 + 13 + 13 = 44, so the perimieter of the rectangle is 44 units.
Answer:
hi Step-by-step explanation:April 12, 1861: Battle of Fort Sumter. ...
June 30, 1861: Battle of Philippi. ...
July 21, 1861: First Battle of Bull Run/First Battle of Manassas. ...
August 28-29, 1861: Battle of Hatteras Inlet Batteries. ...
October 21, 1861: Battle of Ball's Bluff. ...
November 7, 1861: Battle of Belmont. ...
January 19, 1862: Battle of Mill Springs.