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Ivan
3 years ago
6

The depth of water near a boat dock is collected by a buoy. The data shows that the water level reached 11 feet during high tide

at 2:00am and a level of 8 feet during low tide at 9:00am. The depth can be modeled by a sinusoidal function. How deep will the water be at noon? Round your answer to the nearest hundredth. HINT: The equation that models this is y=1.5sin (25.72(x+1.5))+9.5
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
3 0

9514 1404 393

Answer:

  9.17 ft

Step-by-step explanation:

Put x=12 in the equation and evaluate. (The sine argument is in degrees.)

  y = 1.5·sin(25.72(12 +1.5)) +9.5 = 1.5·sin(347.22) +9.5

  y = -0.33 +9.5 = 9.17

The water will be 9.17 feet deep at noon.

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Can someone please clearly and correctly work out Q19? Would appreciate it a lot! :)
DiKsa [7]
x^{2} +10x+30
I always start by moving the last term to the other side
x^{2} +10x=-30
To complete the square you take term 'b' , divide it by 2 then square it
( \frac{10}{2} )^2 = 25
We have to add 25 to what we have and what you do to one side you have to do to the other
x^{2} +10x+25=-30+25
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Now we factor what is on the left side of the equation
(x+5)^2=-5
The last step is to move our right side of the equation back over 
(x+5)^2+5 - which is your answer :)))


6 0
3 years ago
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