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Ivan
3 years ago
6

The depth of water near a boat dock is collected by a buoy. The data shows that the water level reached 11 feet during high tide

at 2:00am and a level of 8 feet during low tide at 9:00am. The depth can be modeled by a sinusoidal function. How deep will the water be at noon? Round your answer to the nearest hundredth. HINT: The equation that models this is y=1.5sin (25.72(x+1.5))+9.5
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
3 0

9514 1404 393

Answer:

  9.17 ft

Step-by-step explanation:

Put x=12 in the equation and evaluate. (The sine argument is in degrees.)

  y = 1.5·sin(25.72(12 +1.5)) +9.5 = 1.5·sin(347.22) +9.5

  y = -0.33 +9.5 = 9.17

The water will be 9.17 feet deep at noon.

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2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de
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Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

               M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let (x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⇒ d=\sqrt{(2-5)^2+(4-3)^2}

⇒d=\sqrt{9+1}

⇒d=\sqrt{10}   ....(1)

Now, we find the length of M'K'

let (x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)

d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}

⇒ d^{'}=\sqrt{(-2+5)^2+(3-4)^2}

⇒d^{'}=\sqrt{9+1}

⇒d^{'}=\sqrt{10} .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct


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