The depth of water near a boat dock is collected by a buoy. The data shows that the water level reached 11 feet during high tide
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We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer is
point (-5,12)
see the attached figure
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer is
point (-5,12)
see the attached figure
Answer: The parametric is being tested here is "p" (population proportion).
The hypothesis test is left-tailed.
Step-by-step explanation:
Given : The null and alternative hypotheses are
The parametric is being tested here is "p", where p stands for population proportion.
Also, the type of test depends on the alternative hypotheses.
Since the alternative hypotheses is left-tailed, so the hypothesis test is left-tailed.
Assuming that 
is the amount of hours spent doing homework:
Plug in
for
, 
That means that since a
value is the test score (because that's what the y-axis is labeled), your predicted test score is a 64.
Plug in
That means that since a