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ELEN [110]
3 years ago
11

Given the following information, find the probability that a randomly selected dog will be a golden retriever or a poodle. Numbe

r of dogs who are poodles: 31, golden retrievers: 58, beagles: 20, pugs: 38a) 39.5%b) 60.5%c) 58.0%d) 46.9%
Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer: a) 39.5%

Step-by-step explanation:

<em>For random selections, we assume that all the dogs have the same probability of being selected.</em>

In this case, the probability will be equal to the number of golden retrievers divided the total number of dogs.

We have 58 golden retrievers, and the total number of dogs is:

31 + 58 +20 + 38 = 147

Then the probability is:

P = 58/147 = 0.395

If we multiply it by 100%, we obtain the percentage form:

0.395*100% = 39.5%

So the correct option is a.

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Select all the options that have the same value as 3 1/2% of 20?
r-ruslan [8.4K]

Solution:

As, we have to find , 3 \frac{1}{2} of 20=\frac{7}{2}% of 20

= \frac{7}{2\times 100}\times 20\\\\ = \frac{7}{10}  \\\\ =0.70

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8 0
3 years ago
What values do x and y have if |x| = 16, |y| = 16, and when x and y are combined they equal 0?
True [87]

If x = 16 and y = -16, then x+y = 16+(-16) = 0

Alternatively, if x = -16 and y = 16, then x+y = -16+16 = 0

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5 0
4 years ago
Read 2 more answers
Find the altitude of triangle whose vertex is a(1,-2) and the equation of the base is X+y=3.
Sophie [7]

Answer:

2\sqrt {2}

Step-by-step explanation:

<u>Distance From a Point to a Line</u>

Given a line with an equation :

ax + by + c = 0

And the point (x_0,y_0)

The distance from the line to the point is given by

\displaystyle d=\frac {|ax_{0}+by_{0}+c|}{\sqrt {a^{2}+b^{2}}}

The triangle has a vertex at (1,-2) and the base lies on the equation

x + y = 3

Rearranging:

x + y - 3 = 0

The altitude of the triangle is the distance from the point to the line.

The values to use in the formula of the distance are: a=1, b=1, c=-3, xo=1, yo=-2:

\displaystyle d=\frac {|1*1+1*(-2)-3|}{\sqrt {1^{2}+1^{2}}}

\displaystyle d=\frac {|1-2-3|}{\sqrt {2}}

\displaystyle d=\frac {4}{\sqrt {2}}

Rationalizing:

\displaystyle d=\frac {4}{\sqrt {2}}\cdot\frac{\sqrt {2}}{\sqrt {2}}

\displaystyle d=2\sqrt {2}

The altitude of the triangle is \mathbf{4\sqrt {2}}

6 0
3 years ago
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