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4 years ago

What is the length of CD?

Mathematics

1 answer:

Eduardwww [97]4 years ago

6 0

Answer:

Step-by-step explanation:

Standard CDs have a diameter of 120 millimetres (4.7 in) and can hold up to about 80 minutes of uncompressed audio or about 700 MiB of data. The Mini CD has various diameters ranging from 60 to 80 millimetres (2.4 to 3.1 in); they are sometimes used for CD singles, storing up to 24 minutes of audio, or delivering device drivers.

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3 years ago

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4 years ago

Maja manages a community garden which has rectangular garden plots that are 15 ft by 10 ft. She wants to add a uniform path arou

tiny-mole [99]

The path should be 6.38 feet wide

Let x be the width of the path.

Since the rectangular plot has an area with dimensions 15 ft by 10 ft, we add x to each dimension to give the dimensions of the rectangular plot plus uniform path.

So, the dimensions are 15 + x by 10 + x respectively.

So, the area of the rectangular plot plus uniform path is A

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Since the combined area of the path is 350 square feet, A = 350 ft²

So, (15 + x)(10 + x) = 350

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$x = \frac{-25 +/-\sqrt{25^{2} - 4X1 X (-200)} }{2 X1 } \\x = \frac{-25 +/-\sqrt{625 + 800)} }{2}\\x = \frac{-25 +/-\sqrt{1425} }{2}\\x = \frac{-25 +/-37.75 }{2}\\x = \frac{-25 + 37.75 }{2} or x = \frac{-25 - 37.75 }{2}\\x = \frac{12.75 }{2} or x = \frac{-62.75 }{2}\\x = 6.375 or x = -31.375$

Since x cannot be negative, we choose the positive answer.

x = 6.375 ft

x ≅ 6.38 ft

So, the path should be 6.38 feet wide

Learn more about width of a path here:

brainly.com/question/15382035

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3 years ago