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STALIN [3.7K]
3 years ago
6

Find two numbers sum -12 and their difference is -2 (chapter integers,explanation also)

Mathematics
2 answers:
BaLLatris [955]3 years ago
5 0

Step-by-step explanation:

x+y=-12

x-y=-2

solve by simultaneous equations multiply the second equation by -1

-x-y=2

subtract both equations

y=10

x+10=-12

×=-22

Vsevolod [243]3 years ago
5 0

Answer:

-7 and -5

Step-by-step explanation:

a + b = -12

a - b = -2

2a = -12 + -2 = -14 ----> a = -7

-7 + b = -12 ---> b = -5

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9x + 2

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Then, you add 2, because when you increase in math, you are adding.

Therefore, the final product is 9x + 2.

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Frist you do 6*13

Which equals 78

Then you do 8,500/78

Which equals <span>108.974358974</span>

<span>Then you round it to 109</span>

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A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The
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Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

3 0
3 years ago
According to Boyle’s law, PV= K, what was the volume at the time of the first measurement given the following information? Round
Temka [501]
<h2>Hello!</h2>

The answer is:

The first measurement of volume is equal to 835.23 mL.

<h2>Why?</h2>

Boyle's Law equation can be used when the temperature is kept constant, and it establishes a relation between the pressure and volume, showing that when an ideal gas is kept constant, the pressure and volume are inversely proportional.

So, we Boyle's Law equation states that:

P_{1}V_{1}=P_{2}V_{2}

Where,

P_1=FirstPressure\\V_1=FirstVolume\\P_2=NewPressure\\V_2=NewVolume

Now, if we are looking for the first volume measurement, we need to rewrite the equation as follow:

P_{1}V_{1}=P_{2}V_{2}\\\\V_{1}=\frac{P_{2}V_{2}}{P_{1}}

So, substituting the given information and calculating, we have:

V_{1}=\frac{8.59atm*527mL}{5.42atm}

V_{1}=\frac{4526.93atm.mL}{5.42atm}=835.23mL

Hence, the first measurement of volume is equal 835.23 mL.

Have a nice day!

8 0
3 years ago
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