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WARRIOR [948]
3 years ago
7

Two rectangular prisms have the same volume. the area of the base of the blue prism is 2 1/6 square units. The area of the base

of the red prism is one third that of the blue prism. Which koo statement is true?

Mathematics
1 answer:
sergiy2304 [10]3 years ago
3 0

Answer:

<h3>This shows that the height of the red prism will be three times that of blue</h3>

Step-by-step explanation:

Volume of a prism = 1/3 * base area * height

V = 1/3Bh

Vr = 1/3Brhr...1

Vb = 1/3Bbhb... 2

Let the volume of red prism be Vr and the volume of blue prism be Vb. If both prisms have the same volume then Vr = Vb = V.

Also if the area of the base of the red prism is one third that of the blue prism, the B, then Br = 1/3 Bb where Bb = 3Br..(3)

Since the volume are the same then;

1/3Brhr =  1/3Bbhb

Substituting equation 3 intio the resulting expression;

1/3Brhr =  1/3(3Br)hb

hr = 3hb

This shows that the height of the red prism will be three times that of blue

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I. In a shipment of 300 connecting rods, the mean tensile strength is found to be 45 kpsi and has a standard deviation of 5 kpsi
CaHeK987 [17]

Answer:

a) Between 39 and 40 rods can be expected to have a strength less than 39.4 kpsi.

b) 260 rods are expected to have a strength between 39.4 and 60 kpsi

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 45, \sigma = 5

(a) Assuming a normal distribution, how many rods can be expected to have a strength less than 39.4 kpsi?

The percentage of rods with a stength less than 39.4 is the pvalue of Z when X = 39.4. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.4 - 45}{5}

Z = -1.12

Z = -1.12 has a pvalue of 0.1314

13.14% of rods have a strength less than 39.4 kpsi.

Out of 300

0.1314*300 = 39.42

Between 39 and 40 rods can be expected to have a strength less than 39.4 kpsi.

(b) How many are expected to have a strength between 39.4 and 60 kpsi?

The percentage of rods with a stength in this interval is the pvalue of Z when X = 60 subtracted by the pvalue of Z when X = 39.4. So

X = 60

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 45}{5}

Z = 3

Z = 3 has a pvalue of 0.9987

X = 39.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.4 - 45}{5}

Z = -1.12

Z = -1.12 has a pvalue of 0.1314

0.9987 - 0.1314 = 0.8673

86.73% of the rods are expected to have a strength between 39.4 and 60 kpsi

Out of 300

0.8673*300 = 260

260 rods are expected to have a strength between 39.4 and 60 kpsi

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

1 in²=6.45 cm²

598 cm²=x in²

  1 in²            x in²

______ = _______

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Cross multiply

6.45x=598

divide both sides by 6.45

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Answer=92.7 in²

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