If a cubic polynomial has zeros at x= -4, x=0 and x=7, then

Mathematics

2 answers:

34kurt3 years ago

7 0

Answer:

Step-by-step explanation:

The Fundamental theorem of algebra tells us that a polynomial of degree n has n roots.

Here the polynomial is a cubic, that is of degree 3

Thus it will have 3 roots, real and/ or imaginary.

Since imaginary roots occur in conjugate pairs

Since the polynomial has 3 real roots there are no imaginary roots, thus

A is the required response.

maw [93]3 years ago

5 0

I think the answer ia A that what i think

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2 years ago

Write the point slope form of the equation of the line using the point (-4,-2)

Gre4nikov [31]

Answer:

$y + 2 = \frac{5}{4} (x + 4)$

Step-by-step explanation:

1) First, find the slope of the line. Take two points the line intersects and use them for the slope formula, $\frac{y_2-y_1}{x_2-x_1}$ . We already know the line intersects (-4, -2). Just choose any one of the points you can see the line intersecting (in this case, I chose (0,3)) and plug in its values, too. Then solve:

$\frac{(3)-(-2)}{(0)-(-4)} \\\frac{3+2}{0+4} \\\frac{5}{4}$

So, the slope is $\frac{5}{4}$ .

2) Now that you have the slope, plug in values for the point-slope formula, $y - y_1 = m (x - x_1)$ . In order to write a linear equation with it, the $x_1$ , $y_1$ , and $m$ have to be substituted for with real values. The $m$ represents the slope - which means that we should place $\frac{5}{4}$ there. The $x_1$ and $y_1$ represent the x and y values of a point - and the questions wants us to use (-4, -2), so substitute -4 for $x_1$ and -2 for $y_1$ :