Start by doing the binomial expansion of (x+y)^6 where x represents success. This is
(x^6y^0) + 6(x^5y^1) +15(x^4y^2) +20(x^3y^3) +15(x^2y^4) +6(x^1y^5) +(x^0y^6)
We are interested in the x^3y^3 term which represents exactly 3 sucesses. Since the probalbility of sucess and failure are both .5 we should be able to figure this out just using the coefficients of the terms which is
20/64 = .3125 which is 31.25%
Answer:
27°
Step-by-step explanation:
- A tangent meets a radius at 90°
- Angles in a trainable sum to 180°
- 180 - 90 - 63 = 27°
Answer:
7a-42
Step-by-step explanation:
you use the disturbtive property ( a (b-c)= ab-ac)
Answer:
7 + 4
Step-by-step explanation:
note that 
× = a
Given
(2 + )² = (2 + )(2 + )
Each term in the second factor is multiplied by each term in the first factor, that is
2(2 + ) + (2 + ) ← distribute both parenthesis
= 4 + 2 + 2 + 3 ← collect like terms
= 7 + 4
Answer:
(5,2)
Step-by-step explanation:
