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anygoal [31]
3 years ago
14

If a cubic polynomial has zeros at x= -4, x=0 and x=7, then

Mathematics
2 answers:
34kurt3 years ago
7 0

Answer:

A

Step-by-step explanation:

The Fundamental theorem of algebra tells us that a polynomial of degree n has n roots.

Here the polynomial is a cubic, that is of degree 3

Thus it will have 3 roots, real and/ or imaginary.

Since imaginary roots occur in conjugate pairs

Since the polynomial has 3 real roots there are no imaginary roots, thus

A is the required response.

maw [93]3 years ago
5 0
I think the answer ia A that what i think
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What is the answer and how did you get it
fredd [130]

The distance should be .625 of an inch. You get this by diving 11.25 by 18.

8 0
3 years ago
Find the product of 8x93 using distributive property. Show the steps and the solution
lesya692 [45]

Explanation:

Distributive property: → a(b+c)=ab+ac

Multiply by the numbers from left to right.

93*8=744

Then, you can also divide into the numbers.

744/8=93

744/93=8

Product it's going to be multiply by the numbers, fractions, factors, and multiples.

Hope this helps!

Thanks!

Have a great day!

3 0
3 years ago
Read 2 more answers
CAN SOMEONE PLEASE SOLVE THIS????????
defon
Which one question? there is multiple in there.
3 0
3 years ago
Select all that apply.
Svetach [21]
I believe the correct answer from the choices listed above is option B. Mixtures are not given chemical formulas because no chemical bonding took place between the components in the mixture such as sugar in water. Sugar in water still remains to be sugar, its properties are the same but only it is dissolved in water.
8 0
3 years ago
Read 2 more answers
Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
Margaret [11]
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
 
Distance traveled by car A =x,  (when the car B is at the same distance from the start line)
time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

x=15(t-3)  (2)

With the equations (1) and (2) we make a system of equations:

x=10t
x=15(t-3)

We solve this system of equations:

10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9

t-3=9-3=6

x=10 t=10 (9)=90

Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
8 0
3 years ago
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