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Romashka-Z-Leto [24]
2 years ago
10

Question 6 (Essay Worth 10 points)

Mathematics
1 answer:
Scilla [17]2 years ago
4 0

Answer:

If you translate the center of circle y up 6 units and to the left 6 units and then dilate the circle with a scale factor of 2, circles x and y would be congruent.

Step-by-step explanation:

If you translate the center of circle y up 6 units and to the left 6 units and then dilate the circle with a scale factor of 2, circles x and y would be congruent.

You might be interested in
3y-6 divided by 9 = 4-2 divided by -3
sweet [91]

Answer:

y = 16/9

Step-by-step explanation:

Assuming "y" is a variable

3y - 6/9 = 4 - 2/-3

3y - 2/3 =14/3

3y - 16/3 = 0

1/3 (9y - 2) = 14/3

ANSWER = y : 16/9

4 0
3 years ago
Read 2 more answers
Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.<b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
8 0
3 years ago
Gray can ride his bike 6miles in 20 minutes at this rate how many miles can he ride in 100 minutes
oksano4ka [1.4K]
30. Since he can ride the bike 6 miles in 20 mins, and 100 divided by 20 is 5, the answer would be given to you by multiplying 5x6, which is 30. So he can travel 30 miles in 100 minutes.
4 0
2 years ago
X=8 units and h=5 units what is the area of the triangle
kykrilka [37]
Area=20. Ur welcome!
4 0
4 years ago
PLEASE HELP ME WITH THIS MATH!!!!!!!!!. pLeAsE i ReAlLy NeEd SoMe HeLp
KonstantinChe [14]
Part 1) we know that
m∠5=44°    m∠11=86°
m∠2=m∠5------> by vertical angles
m∠2=44°
m∠13=m∠11------> by vertical angles
m∠13=86°
m∠12+m∠13=180°-----> supplementary angles
m∠12=180-86-----> m∠12=94°
m∠14=m∠12----> by vertical angles
m∠14=94°
m∠1=m∠11----> by corresponding angles
m∠1=86°
m∠4=m∠1----> by vertical angles
m∠4=86°
m∠2+m∠1+m∠6=180
m∠6=180-(86+44)----> 50°
m∠6=50°
m∠3=m∠6----> by vertical angles
m∠3=50°
m∠8=m∠3----> by corresponding angles
m∠8=50°
m∠8+m∠7=180°-----> supplementary angles
m∠7=180-50----> 130°
m∠7=130°
m∠10=m∠6----> by corresponding angles
m∠10=50°
m∠10+m∠9=180°-----> supplementary angles
m∠9=180-50-----> 130°
m∠9=130°

the answers Part 1) are
m∠1=86°
m∠2=44°
m∠3=50°
m∠4=86°
m∠5=44° 
m∠6=50°
m∠7=130°
m∠8=50°
m∠9=130°
m∠10=50°
m∠11=86°
m∠12=94°
m∠13=86°
m∠14=94°

Part 2) 
a) what is m∠TPR?
in the right triangle PTR 
m∠PTR+m∠TPR+m∠TRP=180° ( the sum of internal angles of triangle is equal to 180 degrees)
m∠PTR=30°
m∠TRP=90°
so
m∠TPR=180-(90+30)----> 60°

the answer Part 2a) is 
m∠TPR=60°

b) what is the length in inches of segment PR?
in the right triangle PTR 
sin 30=PR/TP-----> PR=TP*sin 30-----> PR=14*(1/2)----> 7 in

the answer Part 2b) is
PR=7 in

c)  what is the length in inches of segment TR?
in the right triangle PTR 
cos 30=TR/PT-----> TR=PT*cos 30-----> TR=14*(√3/2)---> TR=7√3 in

the answer Part 2c) is
TR=7√3 in

d)  what is the length in inches of segment PQ?
in the right triangle PQR
PR=7 in
RQ=PR-----> by angle 45°
so
RQ=7 in
applying the Pythagoras Theorem
PQ²=RQ²+PR²-----> 7²+7²-----> PQ²=98-----> PQ=√98 in---> PQ=7√2 in

the answer Part 2d) is
PQ=7√2 in

Part 3) Patrice buys a block of wax in the shape of a right rectangular prism. The dimensions of the block are 20 cm by 9 cm by 8 cm.
  <span><span>(a)   </span>What is the volume of the block?

volume of the prism=20*9*8-----> 1440 cm³

the answer Part 3 a) is
the volume of the block is 1440 cm³
<span>
Patrice melts the wax and creates a candle in the shape of a circular cylinder that has a diameter of 10 cm and a height of 15 cm.<span>(b)   </span>To the nearest centimeter, what is the volume of the candle?
</span></span>volume of a cylinder=pi*r²*h
diameter=10 cm
radius r=10/2----> 5 cm
h=15 cm
volume of a cylinder=pi*5²*15----> 1177.5 cm³-----> 1178 cm³

the answer Part 3b) is
the volume of the candle is 1178 cm³

<span>Patrice decides to use the remaining wax to create a candle in the shape of a cube.<span>(c)   </span>To the nearest centimeter, what is the length of the side of the cube?
</span>
the remaining wax=volume of the prism-volume of a cylinder
=1440-1178-----> 262 cm³

volume of a cube=b³
where b is the length side of the cube
262=b³-------b=∛262-----> b=6.40 cm-----> b=6 cm

the answer Part 3c) is
the length of the side of the cube is 6 cm
5 0
3 years ago
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