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3 years ago

What is the measure of JKL? A. 60° B. 80° C. 110°D. 120 from edge 2020

Mathematics

1 answer:

mixas84 [53]3 years ago

7 0

Answer:

If its from the Ed assignment, it would be D. 120. Though this is a late reply.

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Solution to the system y=-x2-3x+2 y=x+6

worty [1.4K]

Answer:

$x=-2,y=4$

Step-by-step explanation:

$y=-x^2-3x+2$

$y=x+6$

$x+6=-x^2-3x+2$

$x^2+x+6=-3x+2$

$x^2+4x+6=2$

$x^2+4x+4=0$

$(x+2)(x+2)=0$

$x=-2$

$y=(-2)+6=4$

8 0

2 years ago

A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar

ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let $\mu$ = mean waiting time for bus number 14.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 10 minutes {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, $H_A$ : $\mu$ < 10 minutes {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean waiting time = 7.8 minutes

s = sample standard deviation = 2.5 minutes

n = sample of different occasions = 18

So, test statistics = $\frac{7.8-10}{\frac{2.5}{\sqrt{18} } }$ ~ $t_1_7$

= -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0

3 years ago

Find the area bounded by the graphs of the indicated equations over the given interval.

NeX [460]

Answer:

Step-by-step explanation:

$y = 0$

is basically the horizontal axis.

First, find the integral of x^2-25.

Remember that

integral of a constant is that constant times x.

Also that

to take the integral of a power function, add 1 to the degree and divide by that same degree.

$y = {x}^{2} - 25$

We then get

$\frac{ {x}^{3} }{3} - 25x$

Evaluate at -3

$\frac{ - 3 {}^{3} }{3} - 25( - 3)$

$- 27 + 75 = 48$

Then we evaluate at 0

$\frac{0 {}^{3} }{3} - 25(0) = 0$

Next, we subtract the the answer then we get

$48 - 0 = 48$

8 0

2 years ago

Please help !!!!!!!!!!!!

zhannawk [14.2K]

Answer:

25+40

Step-by-step explanation:

for the area of a triangle you multiple the base times the height. for the area of the square it is the length times width.

NOTE: to completely answer just add 25+40

6 0

3 years ago

A rectangle with length 11 feet and width 10 feet. A smaller rectangle with length 3 feet and width 2 feet is cut out of the lar

nikdorinn [45]

Answer:

Step-by-step explanation:

11 * 10 equals 110

3 * 2 equals 6

110 - 6 = 104

7 0

3 years ago

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