The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j. Hence, The vector AB is 16i + 12j.
<h3>How to find the vector?</h3>
If we have given a vector v of initial point A and terminal point B
v = ai + bj
then the components form as;
AB = xi + yj
Here, xi and yj are the components of the vector.
Given;
The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j.
magnitude

Unit vector in direction of resultant = (4i + 3j) / 5
Vector of magnitude 20 unit in direction of the resultant
= 20 x (4i + 3j) / 5
= 4 x (4i + 3j)
= 16i + 12j
Hence, The vector AB is 16i + 12j.
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Answer:
206
Step-by-step explanation:
I put it in a calculator
Answer:
Adding them together. x = 3/2, y = 8
Step-by-step explanation:
Adding because we want to get rid of a variable. If we add, 2x + 6x = 8x, 1/2 * y + (-1/2 * y) = 0, and 7 + 5 = 12. Adding gets rid of the y variable.
By adding we get that 8x = 12 which gives us x = 12/8 = 3/2
Substituting this back into either equation will give us y = 8.
31.62
You use pythagorean theorem so 30 is legA and 10 is legB so 20^2+10^2= square root legC which is 31.62
Answer:
i think its B or A
Step-by-step explanation: