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4 years ago

The arithmetic sequence a; is defined by the formula:

Mathematics

1 answer:

Morgarella [4.7K]4 years ago

6 0

Answer:

The sum of the first 650 terms of the given arithmetic sequence is 2,322,775

Step-by-step explanation:

The first term here is 4

while the nth term would be ai = a(i-1) + 11

Kindly note that i and 1 are subscript of a

Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula

Sn = n/2[2a + (n-1)d)

Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.

Plugging these values, we have

Sn = (650/2) (2(4) + (650-1)11)

Sn = 325(8 + 7,139)

Sn = 325(7,147)

Sn = 2,322,775

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3 years ago

Read 2 more answers

8/3(z+11)=y solve for z.

bagirrra123 [75]

Answer:

z = (3/8)y - 11

Step-by-step explanation:

Undo what has been done to z, in reverse order. Here, 11 is added and the sum is multiplied by 8/3.

To undo the multiplication, multiply the equation by the inverse, 3/8:

(3/8)(8/3)(z+11) = (3/8)y

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4 years ago

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Ksenya-84 [330]

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3 years ago

What is the answer to this equation 1/3÷4/5

Damm [24]

Answer:

5/12

Step-by-step explanation:

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3 years ago

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A greeting card company can sell cards for $2.75 each, so the revenue can be calculated using the formula 2.75 Rx . The company’

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Given that the revenue equation is $R(x)=2.75x$ and the cost equation is $C(x)=0.35x+12,000$

Part A:

At break-even the cost is equal to the revenue.

Thus, the algebraic equation needed to determine when the company will break even is given by

$R(x)=C(x) \\ \\ \Rightarrow2.75x=0.35x+12,000$

Part B:

The solution to part A is given as follows:

$2.4x=12,000 \\ \\ \Rightarrow x=5,000$

Part C:

<span>The algebraic inequality needed to indicate that the revenue is greater than the cost is given by

$R(x)\ \textgreater \ C(x) \\ \\ \Rightarrow2.75x\ \textgreater \ 0.35x+12,000$

Part D:

</span>The solution to part C is given as follows:

$2.4x>12,000 \\ \\ \Rightarrow x>5,000$

Part E:

The answer in part D tells us that the the company will make a profit when the produce more than 5000 cards.

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3 years ago