First you have to make them to a common denominator.
5/6 7/12 7/10
50/60 35/60 42/60
from these the greatest value is 35/60 because 35 parts of 60 is bigger than the rest.
so the answer is 7/12
3x - 6 = 4x + 1
3x - 6 + 6 = 4x + 1 + 6
3x = 4x + 7
3x - 4x = 4x + 7 - 4x
X = -7
:)
Answer:
B
Step-by-step explanation:
sorry if its wrong
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
32,870 is the answer. Hope this helps!
