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anygoal [31]
2 years ago
11

What does x-7 over 7-x equal?

Mathematics
1 answer:
ziro4ka [17]2 years ago
3 0

Answer:

-1

Step-by-step explanation:

All you have to do is cancel out the common factor

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What is the product of 5 and four more than a number is nine times the number. What's the number?
Korvikt [17]

Answer:

The number is 5.

Step-by-step explanation:

The product of 5 and 4 more than a number = 9 times the number

Let the number be x;

5(4 + x) = 9x

20 + 5x = 9x

4x = 20

x = 20/5

x = 5.

4 0
2 years ago
The circumference of Circle F is 72 cm. What is the length of Arc DE (the minor arc)?
Tom [10]

You need to first set up the equation:

It would look like 90 divided by 360 multiplied by the given circumference which is 72 cm.

So 90 / 360 x 72

Simply the fraction above, it will give us:

¼ x 72

So the answer would be 18 cm that is the length of DE (minor arc)

4 0
3 years ago
Read 2 more answers
Identify the postulate that proves the triangles are congruent.
Ratling [72]

Answer:

ASA

Step-by-step explanation:

Triangle ABD is congruent to triangle BDC by ASA because angle B in ABD  is 30 degrees. Then they give you BD which equals BD by the reflexive property. And finally angle D in ABD is also 30 degrees. In triangle BCD, angle B is 30 degrees, BD = BD, and angle D in BCD is 30 degress. So we have an angle (B), side (BD), and another angle (D)

6 0
3 years ago
Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
nirvana33 [79]

Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

5 0
3 years ago
Which expression can be used to determine the slope of the liner function graph below?
Dennis_Churaev [7]
Isn’t there supposed to be a picture?
5 0
2 years ago
Read 2 more answers
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