Answer:
Step-by-step explanation:
1. Null hypothesis: u <= 0.784
Alternative hypothesis: u > 0.784
2. Find the test statistics: z using the one sample proportion test. First we have to find the standard deviation
Using the formula
sd = √[{P (1-P)}/n]
Where P = 0.84 and n = 750
sd =√[{0.84( 1- 0.84)/750]}
sd=√(0.84 (0.16) /750)
SD =√(0.1344/750)
sd = √0.0001792
sd = 0.013
Then using this we can find z
z = (p - P) / sd
z = (0.84-0.784) / 0.013
z =(0.056/0.013)
z = 4.3077
3. Find the p value and use it to make conclusions...
The p value at 0.02 level of significance for a one tailed test with 4.3077 as z score and using a p value calculator is 0.000008254.
4. Conclusions: the results is significant at 0.02 level of significance suck that we can conclude that its on-time arrival rate is now higher than 78.4%.
B. 46 feet because 132/12=11 and 12+12+11+11=46
P=4s
s=p/4
a=s^2, using s found above
a=p^2/16, we were told that p=40 so
a=40^2/16
a=100 in^2
Answer:
x+2
Step-by-step explanation:
x^3+6x^2+11x+6/x^2+4x+3
= x^3+6x^2+11x+6/x^2+4x+3
= (x+1)(x+2)(x+3)/(x+1)(x+3)
=x+2
B for 8 would be 6.2
b for 9 would be 7
The b is adding 0.8 each time
Hope this helps!
