The ratio of a to b is 3 to 1, and the ratio of b to c is 1 to 5. What is the value of 2a+3b/ 4b+3c?

Mathematics

1 answer:

Nostrana [21]3 years ago

6 0

Answer:

Step-by-step explanation:

Expressing the ratios as fractions, that is

$\frac{a}{b}$ = $\frac{3}{1}$ ( cross- multiply )

a = 3b

$\frac{b}{c}$ = $\frac{1}{5}$ ( cross- multiply )

c = 5b

------------------------------------------

Given

$\frac{2a+3b}{4b+3c}$ , substitute values from above for a and c

= $\frac{2(3b)+3b}{4b+3(5b)}$

= $\frac{6b+3b}{4b+15b}$

= $\frac{9b}{19b}$ ← cancel b on numerator/ denominator

= $\frac{9}{19}$ → B

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