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hammer [34]
3 years ago
8

Sally shares 36 pencils between 9 friends. How many pencils did each friend receive?

Mathematics
2 answers:
horsena [70]3 years ago
8 0

36 pencils ÷ 9 friends = 4 pencils per friend

Each friend received 4 pencils.

Hope this helps!! :)

Debora [2.8K]3 years ago
7 0

Answer:

4

Step-by-step explanation:

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CORRECT ANSWER GETS BRAINLY PLEASE!!! For g(x)=x^2-x, find g(x) when x=-5
Gre4nikov [31]
We will plug in -5 for x in the original equation
g(-5) = (-5)^2 - (-5)
we will first square -5
g(-5) = 25 + 5
g(-5) = 30
4 0
3 years ago
Here are three sequences of numbers. The first three numbers are related by a specific pattern that produces the fourth number.
posledela

Step-by-step explanation:

The pattern is

\frac{4^2}{2}=\frac{16}{2}=8\\\frac{3^2}{3}=\frac{9}{3}=3

Thus the missing number is

6 0
4 years ago
A hyperbola centered at the origin has a vertex at (9, 0) and a focus at (−15, 0). Which are the equations of the asymptotes? y
chubhunter [2.5K]
Well, we know is centered at the origing, thus h,k are just 0,0.

using the provided vertex and focus point, gives us a distance for "a" of 9 and a distance for "c" of 15, check the picture below.

\bf \textit{hyperbolas, horizontal traverse axis }\\\\
\cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h\pm a,  k)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2+ b ^2}\\
\textit{asymptotes}\quad  
y= k\pm \cfrac{b}{a}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
a=9\\
c=15
\end{cases}\implies c=\sqrt{a^2+b^2}\implies \sqrt{c^2-a^2}=b
\\\\\\
\sqrt{15^2-9^2}=b\implies \sqrt{144}=b\implies \boxed{12=b}\\\\
-------------------------------\\\\
asymptotes\qquad y=0\pm\cfrac{12}{9}(x-0)\implies y=\pm\cfrac{4}{3}x

3 0
4 years ago
Read 2 more answers
Two six sided die are rolled, one after another. In the sample space of all possible results, how many of the sums are not great
Softa [21]
There are only 3 patterns that exceed the sum of 10 which are: 5-6,6-5,6-6.
Which gives us 33 patterns. Which makes 33 sums not greater than 10.
7 0
3 years ago
Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and
inn [45]

Complete Question

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.1 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.)  

t=8.169  

P-value= ?

Answer:

a)  P-value=0

b)  Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/  cellulose composite exceeds 48 MPa.

Step-by-step explanation:

From the question we are told that:

Sample size n=10

Mean \=x= 51.3

Standard deviation \sigma=1.2

Significance level is taken as \alpha=0.05

t test statistics

t=8.169

Therefore

P-Value=P(t>8.169)

Critical point

t_{\alpha,df}

\alpha=0.05

df=10-1=>9

Therefore

P-value from T distribution table

P-value=0

Conclusion

P-value (0)< \alpha(0.05)

We Reject the Null Hypothesis H_0

Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/  cellulose composite exceeds 48 MPa.

7 0
3 years ago
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