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JulsSmile [24]
2 years ago
11

Can someone tell me what 12x4 is

Mathematics
2 answers:
Kruka [31]2 years ago
5 0

Answer:

48

Step-by-step explanation:

Mazyrski [523]2 years ago
5 0

Answer:

I think it's 48

☆┌─┐ ─┐☆

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│▒│/▒/

│▒ /▒/─┬─┐◯

│▒│▒|▒│▒│

┌┴─┴─┐-┘─┘

│▒┌──┘▒▒▒│◯

└┐▒▒▒▒▒▒┌┘

◯└┐▒▒▒▒┌

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The sum of three consecutive numbers is 72 what is the smallest of the numbers
mylen [45]

Answer:

23

Step-by-step explanation:

Suppose,

the first number = x

the second number = x+1

the third number = x+1+1 = x+2

Question wise,

x+x+1+x+2 = 72

3x+3 = 72

3x = 72-3 = 69

x = 69/3 = 23

so the numbers are,

23,(23+1)=24 and (23+2)=25

6 0
2 years ago
Andrew believes the honor roll students at his school have an unfair advantage in being assigned to the math class they request.
Artist 52 [7]
<span>                                                            Honor roll Not on honor roll Total
Received math class requested        315               64                   379
Did not get math class requested        41               80                   121
Total                                                        356             144                   500 

Honor roll: request granted: 315/356 = 0.88 x 100% = 88%
Not Honor roll request granted: 64/144 = 0.44 x 100% = 44%

Honor roll students were given preference in granting request than those not in the honor roll.</span>
5 0
3 years ago
26. Use the diagram given below to answer the questions that follow. Diameter = 18cm (Use r = 3.14) a. Find the area of the circ
UkoKoshka [18]

Answer:

a. 254.34, b. 56.52

Step-by-step explanation:

a. A = πr^2,

A = 3.14(9^2)

A = 3.14*81

A = 254.34

b. C = πd

C = 18*3.14

C = 56.52

3 0
2 years ago
James has $7.60 in nickels and quarters. He has 4 fewer nickels than quarters. How many of each coin does he have? ​
Rainbow [258]
26 quarters, 22 nickels
4 0
2 years ago
Solve 3x2 + 4x = −5.
Alla [95]
Move the -5 over by adding 5 to both sides
3x^2+4x+5=0
must use quadratic formula

for an equation in the form
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

a=3
b=4
c=5

x=\frac{-4+/- \sqrt{4^2-4(3)(5)} }{2(3)}
x=\frac{-4+/- \sqrt{16-60} }{6}
x=\frac{-4+/- \sqrt{-44} }{6}
x=\frac{-4+/- 2\sqrt{-11} }{6}
remember that√-1=i
x=\frac{-4+/- 2i\sqrt{-11} }{6}
x=\frac{-2+/- i\sqrt{-11} }{3}

x=\frac{-2+ i\sqrt{-11} }{3} or x=\frac{-2- i\sqrt{-11} }{3}


4 0
3 years ago
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