Answer:
Advantages of hardware:
Physical existence
Multitasking
Speedy
Disadvantages:
Costly as different equipment cost differently
Time consuming
requires space
Privacy issues
Explanation:
Advantages of Software:
Less costly
Improved privacy controls
Requires no space
Disadvantages:
Does not have physical existence
hacking and cyber attacks may steal important information
Regular updates required
Answer:
5, 10 and 16
Explanation:
The sum of their ages is √961 = 31
If Joe is x years old, the equation that follows is:
x + (x+5) + (x+5+6) = 31
This simplifies to
3x = 31 - 11 - 5 = 15
so x=5
From that you can find
Joe = x = 5
Kate = x+5 = 10
Jody = x+5+6 = 16
Answer:
The intel core i7 and core i9
advantages;
- The core i7 and core i9 have maximum memory spaces of 64GB and 128GB respectively.
- They both support hyper-threading.
- core i7 has 4 cores and 8 threads while the i9 has 8 cores and 16 threads.
- The maximum number of memory channels for i7 and i9 are 3 and 4 respectively.
- The Base frequencies of core i7 and i9 are 1.10GHz and 3.00GHz respectively.
demerits;
- High power consumption and requires a high-performance motherboard.
- Costly compared to earlier Intel processors
- They do not support error correction code memory, ECC
Explanation:
The intel core i7 and i9 processors are high-performance processors used in computing high-resolution graphics jobs and in processes where speed is required. This feature makes these processors flexible, to be used in most job types.
Note that computers with these processors are costly, must have and be upgraded with a DDR3 RAM chip, and consumes a lot of power to generate high-performance.
Answer:
I will code in Javascript:
function sumOddAndEven(){
<em> //Define and initialize variables.</em>
var numbers = [1,2,3,4,5,6,7,8];
var sum = [0,0];
for ( var i = 0; i < numbers.length ; i++ ){ <em>// loop to go throght the numbers</em>
<em> </em>if(numbers[i] > 0) {<em> // if the number is positive</em>
if(numbers[i]%2 == 0) { <em>// if number is even and </em>
sum[0] = sum[0] + numbers[i]; <em>//adds in the first place of sum</em>
}
else{
sum[1] = sum[1] + numbers[i]; <em>// else adds in the second place of sum</em>
}
}
}
return sum; <em>//return an array with the sum of the positive evens numbers in the first place and the sum of the positive odd numbers in the second place.</em>
}
