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Over [174]
3 years ago
6

Subtract 5/8- 5/12 Enter your answer below as a fraction in lowest terms, using

Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

Answer:

5/8 - 5/12 = (5×3/8×3)-(5×2/12×2)15-10/24 = 5/24

Step-by-step explanation:

first find out the LCM ( Lowest Common Multiple ) of the denominators              ( here:24 ) and multiply the denominator and numerator , both with the required no. to make the denominator as equal as the LCM [( 5×3/8×3 ) -          ( 5×2/12×2)] and subtract / add the numerators. the answer you get is the correct answer.

hope that is helpful for your future.

best of luck

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What is the value of f(-3)
Readme [11.4K]

f(x)=\left\{\begin{array}{ccc}-2&if&x < -3\\4x&if&-3\leq x\leq-1\\x^2&if&x > -1\end{array}\right\\\\-3\leq-3\leq-1\to f(x)=4x\\\\f(-3)=4(-3)=-12

8 0
3 years ago
How to solve this problem
solmaris [256]
Absolute value because for any number given the y or answer will be no less than 0 it will.always be positive
5 0
3 years ago
Which of the following expressions are equivalent? Justify your reasoning,
marshall27 [118]

Answer:

B and D

Step-by-step explanation:

B:

Anything to a negative power means that it is 1/that to the positive power.

E.g. x^-1 = 1/x^1

In other words, anything to the power of a negative switches sides of a fraction (i.e. if in numerator moves to denominator and vice versa.)

1/x^-1 = 1/1/x^1 which is just equal to x, because there are x number of 1/xs in one (1/x * x =1) Therefore Option B is equal to just x.

D: (assuming the first given term is x^1/3 and not X1/3 (?) Correct me if I'm wrong).

x^1/3 * x^1/3 * x^1/3 is also equal to just x.

This is because when multiplying together terms with the same base (x in this case) the exponents just add together, so:

x^1/3 * x^1/3 * x^1/3 = x^(1/3 +1/3 +1/3) = x^1 = x.

Therefore B and D are equivalent because they both equal x.

Hope this helped!

7 0
3 years ago
What is the square root of 1232348 x 2453
katovenus [111]

54981.35 is the square root

7 0
2 years ago
Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ
Allisa [31]

Answer:

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

Step-by-step explanation:

There is a random binomial variable X that represents the number of units come off the line within product specifications in a review of n Bernoulli-type trials with probability of success 0.91. Therefore, the model is {15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}. So:

P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002

P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013

P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082

P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

8 0
3 years ago
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