2 years ago

PLEASE HELP ME!!! PLEASE PLEASE AND PLEASE!

Mathematics

2 answers:

Charra [1.4K]2 years ago

6 0

13-3 is positive and 3-13 is negative

shutvik [7]2 years ago

3 0

Is not because the 13-3 would be positive and the other 3-13 would be negative

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Select the correct answer from each drop-down menu. y = x2 + 2x − 1 y − 3x = 5 The pair of points representing the solution set

katen-ka-za [31]

ANSWER

(-2,-1)

(3,14)

EXPLANATION

The given system is

$y = {x}^{2} + 2x - 1$

$y - 3x = 5$

$y = 3x + 5$

Equate both of them:

${x}^{2} + 2x - 1 = 3x + 5$

This implies that,

${x}^{2} - x - 6 = 0$

$(x - 3)(x + 2) = 0$

x=-2 or x=3

When x=-2, y=y=3(-2)+5=-1

(-2,-1) is a solution.

When x=3 , y=3(3)+5=14

(3,14) is also a solution.

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3 years ago