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jasenka [17]
3 years ago
15

You randomly draw a marble out of a bag that contains 202020 total marbles. 121212 of the marbles in the bag are blue. What is \

text{P(draw a blue marble})P(draw a blue marble)start text, P, left parenthesis, d, r, a, w, space, a, space, b, l, u, e, space, m, a, r, b, l, e, end text, right parenthesis? If necessary, round your answer to 222 decimal places.
Mathematics
1 answer:
Vitek1552 [10]3 years ago
8 0

Answer:

<h2>0.60</h2>

Step-by-step explanation:

Probability is defined as the likelihood or chance that an event will occur. IT is expreesed as shown;

Probability = Expected outcome of event/total outcome of event

If a bag contains 20 total marbles, then the total outcome of event is 20.

If 12 blue marbles are selected from the bag, the expected outcome of event will be 12.

Probability of drawing a blue marble P(draw a blue marble)= 12/20

= 0.60 (to 2dp)

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What type of reaction is shown below? Check all that apply. 2Na + Cl2 → 2NaCl synthesis decomposition combustion
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Answer: This is a type of Synthesis reaction.

Explanation:

  • Synthesis reaction is a type of chemical reaction in which two or more substances combine to form a single substance.

A+B\rightarrow AB

  • Decomposition reactions are a type of chemical reactions in which a substance breaks down into two or more substances.

AB\rightarrow A+B

  • Combustion reaction is a type of chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water.

Hydrocarbon+O_2\rightarrow H_2O+CO_2

For the given reaction:

2Na(s)+Cl_2(g)\rightarrow 2NaCl

Here, 2 substances are combining together to form a single substance. Hence, it is considered as a synthesis reaction.

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750 tickets were sold for a game for a total of $1,400.00. If adult tickets sold for $2.50 and children's tickets sold
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3 0
3 years ago
State whether the triangles could be proven congruent, if possible, by SSS or SAS.
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Answer:

1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

Step-by-step explanation:

1) Side FY ≅ Side CW  Given

Side FP ≅ Side CM     Given

Side YP ≅ Side MW    Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT   Given

Side SV ≅ Side SV  by reflexive property

Side VT ≅ Side VU   Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

4. Side MN ≅ Side QP  Given

Side MQ ≅ Side NP     Given

Side NQ ≅ Side NQ    by reflexive property

∴ΔQNM ≅ ΔQNP by the Side-Side-Side (SSS) rule of congruency

5. Indirect proof

Side GL ≅ Side HL  Given

Side GJ ≅ Side HK     Given

∠JLG ≅ ∠HLK    vertically opposite angles

By sine rule

GJ/sin(∠JLG) = GL/n(∠GJL)

Similarly

HK/sin(∠HLK) = HL/n(∠HKL)

∴ ∠GJL ≅ ∠HKL

∴ ∠LGJ ≅ ∠LHK third angle of two triangles given the other two angles are congruent

∴ΔQNM ≅ ΔQNP by the Side-Angle-Side (SAS) rule of congruency

6. ∠XZY ≅ ∠XZW   Supplementary ∠s with ∠XZY = 90°

Side XZ ≅ Side XZ  by reflexive property

Side ZW ≅ Side ZY   Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

3 0
3 years ago
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