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Lelechka [254]
3 years ago
7

Question 1 of 3

Mathematics
1 answer:
ankoles [38]3 years ago
8 0

Answer:

C(L) = 4L + 3600/L (assuming common wall is width)

C(L) = 3L + 4800/L (assuming common wall is length)

Step-by-step explanation:

The area of residence is 1200 sq feet.

LW = 1200

W = 1200/L

The length of one residence is L, and the width is 1200/L.

I assume the common wall is the width.

The total length of the duplex is 2L.

The width is W = 1200/L

Also, the perimeter of the entire duplex is 2L + 2L + W + W.

In addition, there is a common wall whose length is the width of the duplex.

The entire length of cinder block walls is 2L + 2L + W + W + W, but we know that W = 1200/L, so we get

C(L) = 4L + 3W

C(L) = 4L + 3(1200/L)

C(L) = 4L + 3600/L

This is with the assumption that the common wall is a width, not a length.

If the common wall is a length, then we get this.

The perimeter of the entire duplex is L + L + 2W + 2W.

The common wall is a length of the duplex.

The entire length of cinder block walls is L + L + 2W + 2W + L, but we know that W = 1200/L, so we get

C(L) = 3L + 4W

C(L) = 3L + 4(1200/L)

C(L) = 3L + 4800/L

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