Question

Evaluate (4×+4)(7×-3)

Answer 1

Answer:

$28x^{2} +16x-12$

Step-by-step explanation:

$(4x+4)(7x+3)$

Apply FOIL method: $(a+b)(c+d)=ac+ad+bc+bd$

$a=4x,b=4,c=7x,d=-3$

$=4x*7x+4x(-3)+4*7+4(-3)$

Apply minus - plus rules

$+(-a)=-a$

$=4*7xx-4*3x+4*7-4*3$

Simplify $4*7xx-4*3x+4*7-4*3$

$4*7xx$

Multiply the numbers: $4*7=28$

Apply exponent rule: $a^{b} *a^{c} =a^{b+c}$

$xx=x^{1+1}$

$=28x^{1+1}$

Add the numbers: $1+1=2$

$=28x^{2}$

$4*3x$

Multiply the numbers: $4*3=12$

$=12x$

$4*7x$

Multiply the numbers: $4*7=28$

$=28x$

$4*3$

Multiply the numbers: $4*3=12$

$=12$

$=28x^{2} -12x+28x-12$

Add similar elements: $-12x+28x=16x$

$=28x^{2} +16x-12$

$28x^{2} +16x-12$