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melisa1 [442]
2 years ago
12

If the mean of 5 positive integers is 15, what is the maximum possible difference between the largest and the smallest of these

5 numbers?​
Mathematics
1 answer:
Vikki [24]2 years ago
5 0

Answer:

if the 5 numbers are different, the maximum difference is 64

Step-by-step explanation:

We have 5 positive (different) integers, a, b, c, d and e (suppose that are ordered from least to largest, so a is the smallest and b is the largest.

The mean will be:

M = (a + b + c + d + e)/5 = 15.

Now, if we want to find the largest difference between a and e, then we must first select the first 4 numbers as the smallest numbers possible, this is:

a = 1, b = 2, c = 3 and d = 4

M = (1 + 2 + 3 + 4 + d)/5 = 15

M = (10 + d)/5 = 15

10 + d = 15*5 = 75

d = 75 - 10 = 65

then the difference between a and d is = 65 - 1 = 64.

Now, if we take any of the first 4 numbers a little bit bigger, then we will see that the value of d must be smaller, and the difference between d and a will be smaller.

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Answer:

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8 0
2 years ago
Pls help me guys!<br> And Pls explains how you got the answer!<br> Thanks :D
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Answer:

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nasty-shy [4]

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Step-by-step explanation:

7 0
2 years ago
A worker is paid $0.05 on the first day, $0.10 on the second day, $0.20 on the third day, $0.40 on the fourth day, and so on. Ho
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