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CaHeK987 [17]
3 years ago
8

Whats more likely an object is 0,or an object whose weight is 0? Science not mathematics

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0
If an items weight is 0 it would be like a peice of paper or cotten ball. when a cotten ball is weighed it does not affect anything. as when a peice of paper is wieghed it moves its meater 1 inch.
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What is the answer to 140=m+25
DaniilM [7]
You Add 140 + 25 First
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A=12h(b1+b2) solve for b1 please.
Papessa [141]
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belka [17]
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A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
mina [271]

Answer:

The tip of the man shadow moves at the rate of \frac{20}{3} ft.sec

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

\frac{y - x}{y} = \frac{6}{15}

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = \frac{15x}{9\\} y = \frac{5x}{3}

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt} ----(1)

We are given \frac{dx}{dt} = 4 ft/sec. Plug in the equation (1), we get

\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

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nevsk [136]

Answer:

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3 years ago
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